Answer:
1st quartile: 1920s / 6
Step-by-step explanation:
First find the median, which is 1950s / 10. There are 5 rows behind it.
The median of those previous 5 rows is 1920s / 6.
Hello,
Very nice like question!
a)
F(2)=3 ; G(2)=2
F'(2)=0; G'(2)=1/2
P'(x)=F'(x)*G(x)+F(x)*G'(x)
P'(2)=0*2+3*1/2=3/2
b)
F(7)=5; G(7)=1
F'(7)=1/4; G'(7)=-2/3
Q'(x)=(F'(x)*G(x)-F(x)*G'(x)) / G²(x)
Q'(7)=(1/4*1-5*(-2/3))/1²=1/4+5/3=23/12
This the concept of circumference of circle. The arc length will be given by:
C=theta/360*pi*diameter
theta=62
diameter=d
thus the arc length will be:
C=62/360*π*d
C=0.54d
Hello there!
The correct answer is option C
3x + 20x - 55 = -9
I am not sure if you wanted some more details but I hope this helps and if you do, just let me and I will edit it.
Good luck with your studies!
Happy New Year!~
Look at the face of the pyramid facing you. The length of the base of this pyramid is 82 m; half of that is 41 m.
If you were to draw a straight vertical line through the vertex of the pyramid, the bottom of this line would be at the very center of the base and also be 41 in perpendicular distance from any of the edges of the base of this pyramid.
Let the height of the pyramid be y, as measured upward from the center of the base of the pyramid. This center is, as before, 41 m from any side of the pyramid base, a horiz. distance.
Then, tan 52 deg = y / 41 m, and so y = height of pyramid =
(41 m)(tan 52 deg) = (41 m) (1.28) = 52.48 m
