17 is the correct answer.
Answer:
I am not sure sorry
Step-by-step explanation:
The anser i got was 3.33333 but i think you would plot it as 3.25
At heart we're being asked for a line through two points,
![(40^\circ \textrm{ C}, 355 \textrm { m/s}) \quad \textrm{and} \quad (49^\circ \textrm{ C}, 360 \textrm { m/s})](https://tex.z-dn.net/?f=%2840%5E%5Ccirc%20%5Ctextrm%7B%20C%7D%2C%20355%20%5Ctextrm%20%7B%20m%2Fs%7D%29%20%5Cquad%20%5Ctextrm%7Band%7D%20%5Cquad%20%2849%5E%5Ccirc%20%5Ctextrm%7B%20C%7D%2C%20360%20%5Ctextrm%20%7B%20m%2Fs%7D%29%20)
In general the line through (a,b) and (c,d) is
![(y-b)(c-a)=(x-a)(d-b)](https://tex.z-dn.net/?f=%28y-b%29%28c-a%29%3D%28x-a%29%28d-b%29)
Check that you understand why both (a,b) and (c,d) are on this line.
Here our indepedent variable, instead of x, is T, temperature. Our dependent variable is v, velocity. Substituting,
![(v - 355)(49 - 40) = (T - 40)(360 - 355)](https://tex.z-dn.net/?f=%28v%20-%20355%29%2849%20-%2040%29%20%3D%20%28T%20-%2040%29%28360%20-%20355%29)
![9(v - 355) = 5(T - 40)](https://tex.z-dn.net/?f=9%28v%20-%20355%29%20%3D%205%28T%20-%2040%29)
![v-355 = \frac 5 9 T - \frac{200}{9}](https://tex.z-dn.net/?f=v-355%20%3D%20%5Cfrac%205%209%20T%20-%20%5Cfrac%7B200%7D%7B9%7D)
![v= \frac 5 9 T - \frac{200}{9} + 355](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%205%209%20T%20-%20%5Cfrac%7B200%7D%7B9%7D%20%2B%20355)
![v= \frac 5 9 T + \frac{2995}{9}](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%205%209%20T%20%2B%20%5Cfrac%7B2995%7D%7B9%7D)
That's our answer; let's check it.
When T=40, v = (5/9)40 + (2995/9) = 355 good
When T=49, v= (5/9)49 + (2995/9) = 360 good
Answer:
3/7
Step-by-step explanation:
Opposite sides on a parallelogram are parallel, and parallel lines have the same slope, so once we find the slope of AB, we'll know the slope of CD. Point A is (-1,6) and point B is (6,9), so the slope of AB (and by extension, CD) is
![\dfrac{9-6}{6-(-1)}=\dfrac{3}{7}](https://tex.z-dn.net/?f=%5Cdfrac%7B9-6%7D%7B6-%28-1%29%7D%3D%5Cdfrac%7B3%7D%7B7%7D)