A scale on a map is 1mm: 50miles

janine bought a portable CD player for $75. if the sales tax is 5%,what is the total cost of the CD player

Marina CMI [18]

Answer

78.75

Step-by-step explanation:

75.00 × 0.05

= 78.75

3 0

3 years ago

Factor and add steps please<br><br> 81u^6+192

attashe74 [19]

ANSWER : (9u - 8)2

STEPS:

Step-1 : Multiply the coefficient of the first term by the constant 81 • 64 = 5184

Step-2 : Find two factors of 5184 whose sum equals the coefficient of the middle term, which is -144 .

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -72 and -72
81u2 - 72u - 72u - 64

Step-4 : Add up the first 2 terms, pulling out like factors :
9u • (9u-8)

Step-5 : Add up the four terms of step 4 :
(9u-8) • (9u-8)
Which is the desired factorization

5 0

1 year ago

Help please posted picture of question

bagirrra123 [75]

The given equation is:

y = -10x + 1
Slope of this equation = -10

New line will be perpendicular to this line, so slope of new line = 1/10

So, we are to find the equation of a line with slope 1/10 and passing through (5,7). Using the point slope form we can write

y - 7 = 1/10 ( x - 5)
y = x/10 -1/2 + 7
y = x/10 + 13/2
⇒
x/10 - y = -13/2

So option C gives the correct equation of the new line

6 0

3 years ago

The scale model of a skyscraper being built is 4.2 feet tall. When it is finished, the skyscraper will be 525 meters tall. What

Natali [406]

4.2 ft = 525 meters.... So 1 ft = 525÷42=125 meters

6 0

3 years ago

The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%

vagabundo [1.1K]

Answer:

1) $\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

2) $p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

$\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}$

Where O rpresent the observed values and E the expected values.

State the null and alternative hypothesis

Null hypothesis: The distribution is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

$E = \% Grand total$

$E_{Catfish}=500*0.3=150$

$E_{Bass}=500*0.15=75$

$E_{Bluegill}=500*0.4=200$

$E_{Pike}=500*0.15=75$

Part 1: Calculate the statistic

$\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

$\chi^2 =16.313$

Calculate the critical value

First we need to calculate the degrees of freedom given by:

$df= (categories-1)=(4-1)= 3$

Since the confidence provided is 95% the significance would be $\alpha=1-0.95=0.05$ and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be $\chi^2_{crit}=7.815$

We can calculate also the p value:

$p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

5 0

3 years ago