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Before performing any calculation it's good to recall a few properties of integrals:


So we apply the first property in the first expression given by the question:
![\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}](https://tex.z-dn.net/?f=%5Csmall%20%5Csf%7B%5Clongrightarrow%5Cint%20%5E3_%7B-2%7D%20%5B2f%28x%29%20%2B2%5Ddx%3D%202%20%5Cint%20%5E3%20_%7B-2%7D%20f%28x%29%20dx%2B%20%5Cint%20f%5E3%20_%7B2%7D%202dx%3D18%7D)
And we solve the second integral:


Then we take the last equation and we subtract 10 from both sides:


And we divide both sides by 2:


Then we apply the second property to this integral:

Then we use the other equality in the question and we get:


We substract 8 from both sides:

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Answer:
the answer is y =p(t + 4)/2
Since the 7 is in front of the parentheses you must multiply it by everything inside the parentheses. 7 times X is 7X and 7 times -2 is -14. Then you need to make the X be by itself on one side, to do that you have to add 14 to -14 to make it disappear, and also add 14 to the other side, to 28. Then you divide both sides by 7 to make X be by itself.
7(x-2)=28
7X-14=28
7x=42
X=6
Answer:
48 bcoz u do 4(3)+5 do f(g) than for f(17) u do 3(17)-3
2.5(12.75x + 24.50) = 188.75
31.875x + 61.25 = 188.75
31.875x = 188.75 - 61.25
31.875x = 127.50
x = 127.50 / 31.875
x = 4....they worked 4 hrs