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MA_775_DIABLO [31]
3 years ago
7

How do you solve, 3r+2(12r+7)less then or equal to 5r-8

Mathematics
1 answer:
nignag [31]3 years ago
6 0

Answer:

r  ≤ -1

Step-by-step explanation:

Given in the question

<h3>   3r+2(12r+7) ≤  5r-8</h3><h3>It can be solve by Simplifying and Reordering the terms</h3>

3r + 2(12r)  + 2(7) ≤ 5r - 8

3r + 24r + 14 ≤ 5r - 8

27r + 14 ≤ 5r - 8

27r - 5r +14 + 8 ≤ 0

22r + 22  ≤ 0

22r ≤ -22

Move term containing r to the left, all term to the right.

r  ≤ -22/22

simplifying

r  ≤ -1

all negative integers which are smaller than or equal to -1

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