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eduard
3 years ago
10

What additional information is needed to prove the following triangles congruent by ASA?

Mathematics
2 answers:
lianna [129]3 years ago
7 0

Answer:

angle B = angle C

Step-by-step explanation:

______________

Brilliant_brown [7]3 years ago
3 0

Step-by-step explanation:

hdjsje dhd d sis s. sjxjdns

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A part selected for testing is equally likely to have been produced on any one of six cutting tools.
JulijaS [17]

Answer:

a)S= (1,2,3,4,5,6)

b) 1/6 or 16.67%

c) 1/3 or 33.33%

d) 5/6 or 83.33%

Step-by-step explanation:

a) Sample space is the list of all the possible sample in this its either tool 1,2,3,4,5 or 6

b) probability of selecting from tool 1 is equally likely to picking from any cutting tool therefore it

1/6 or 16.7%

c) probability of selecting from any tool is 16.7% so probability of selecting from 3 or 5 = 16.67% + 16.67% = 33.3%

d) if the part is not from tool 4 then its from tool 1, or tool 2 or tool 3 or tool 5 or tool 6 therefore its

1/6+1/6+1/6+1/6+1/6 = 5/6 or 8.33%

8 0
3 years ago
How can you rewrite P(z £ –1.75) in order to find the answer? P(z £ 1.75) P(z ³ -1.75) 1 - P(z £ -1.75) 1 - P(z £ 1.75)
Fudgin [204]
To rewrite it the answer is 1-P(z 1.75) D

5 0
3 years ago
Read 2 more answers
How do I figure this out?
balu736 [363]

it is 1 2 twelve I can end without 20 word my friend so deal with it

6 0
3 years ago
PLEASE HELP ME PLEASE PLEASE
mezya [45]
1)

Break up the irregular shape into two rectangles

12 * 4.5 = 54
2 * 5 = 10
54 + 10 = 64 cm^2

2)

Break up the irregular shape into a triangle and rectangle

24 * 8 = 192

To get the base of the triangle:
24 - 6 - 6 = 12
To get the height of the triangle:
16 - 8 = 8

1/2(12 * 8) = 48

192 + 48 = 240 yd^2

3)

Separate into triangle and semi circle

To get the base: 8 * 2 = 16

1/2(15 * 16) = 120

(pi (8)^2)/2 = 100.5

120 + 100.5 = 220.5 cm^2

4)

Separate half circle from rectangle

(pi (7.5)^2)/2 = 88.4

7 * 15 = 105

88.4 + 105 = 193.4 m^2

5)

Separate triangle from trapezoid

2.8 * 7 = 19.6

(7+9/2)(3.6) = 28.8

19.6 + 28.8 = 48.4 ft^2

6)

Separate semi circle from trapezoid

(pi(3)^2)/2 = 6.3

(6+10/2)(8) = 64

6.3 + 64 = 70.3 yd^2

8 0
3 years ago
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
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