Answer:
13
Step-by-step explanation:
I am amusing you are looking for the hypotenuse since this is middle school.
If you have the legs and are looking for the hypotenuse you use the Pythagorean Theorem 
The legs are a and b, and the hypotenuse is c
The work would look like this
extra notes
- I rounded to 13
- If you didn;t know you cancles exponents with roots
so the 
is cancled by aka 
Hope this helped :)
Answer: 6 and 1/12 cups
Step-by-step explanation:
For this problem, we add 3 and 2/3 + 1 and 3/4 + 2/3. We can change these mixed numbers into improper fractions to make the math easier:
11/3 + 7/4 + 2/3
Next, we can add the 11/3 and 2/3 since they have the same denominator (bottom number). This gives us 13/3.
13/3 + 7/4
Now that we have two fractions, we just add them together. This leaves us with 6 and 1/2.
If you're having trouble with adding fractions with denominators that aren't the same, here are some videos (if you can't click the link, just copy and paste into the search bar):
<u>https://youtu.be/bcCLKACsYJ0</u> -- Khan Academy
<u>https://youtu.be/5juto2ze8Lg</u> -- Math Antics
Answer:
D
Step-by-step explanation:
Answer:
thats a statement
Step-by-step explanation:
1. Find the equation of the line AB. For reference, the answer is y=(-2/3)x+2.
2. Derive a formula for the area of the shaded rectange. It is A=xy (where x is the length and y is the height).
3. Replace "y" in A=xy with the formula for y: y= (-2/3)x+2:
A=x[(-2/3)x+2] This is a formula for Area A in terms of x only.
4. Since we want to maximize the shaded area, we take the derivative with respect to x of A=x[(-2/3)x+2] , or, equivalently, A=(-2/3)x^2 + 2x.
This results in (dA/dx) = (-4/3)x + 2.
5. Set this result = to 0 and solve for the critical value:
(dA/dx) = (-4/3)x + 2=0, or (4/3)x=2 This results in x=(3/4)(2)=3/2
6. Verify that this critical value x=3/2 does indeed maximize the area function.
7. Determine the area of the shaded rectangle for x=3/2, using the previously-derived formula A=(-2/3)x^2 + 2x.
The result is the max. area of the shaded rectangle.
