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9966 [12]
3 years ago
7

PLEASE!!!!A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the

function h(t) = −16t2+48t+8. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball's maximum height?
Mathematics
1 answer:
kati45 [8]3 years ago
4 0

Answer:

57ft feet is the answer I think

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One of my cats, Apollo, drives a cat car. He used 6/8 of a tank of gas to visit his friends for the weekend, and another 1 half
Arlecino [84]

Answer:

Total gas used = 3/2 of a tank of gas

Step-by-step explanation:

Visit to friend = 6/8 of a tank of gas

Commute to work = 1/2 of a tank of gas

Weekend trip = 1/4 of a tank of gas

Total gas used = Visit to friend + Commute to work + Weekend trip

= 6/8 + 1/2 + 1/4

= 6+4+2/8

= 12/8

= 3/2

Total gas used = 3/2 of a tank of gas

7 0
3 years ago
Dario bakes a lasagna containing 2/3 pound of parmesan cheese, 5/4 pounds of ricotta cheese, and 4/3 pounds of mozzarella cheese
kap26 [50]
First, we have to figure out how much cheese we have total. Do this by adding up all of the various cheeses.

\frac{2}{3}  +  \frac{4}{3}  +  \frac{5}{4} \\  \frac{6}{3}  + 1 +  \frac{1}{4}  \\ 3 \frac{1}{4}
Now to split the cheeses into sections of 1/4 pound each, we have to divide by 1/4, which is the same as multipling by 4

3 \frac{1}{4}  \times 4 = 12 + 1 = 13

13 slices total
5 0
3 years ago
The probability that you roll a 3 on a six-sided die is . The probability that you flip a coin that lands on tails is . The prob
aivan3 [116]

Answer:

1/6; 1/2; 1/12; P(T|3) = 1/2; therefore, events are independent because P(T|3) = P(T).

Step-by-step explanation:

The probability of rolling a 3 on a six-sided die is 1/6.  This is because there is one 3 out of 6 possibilities.

The probability of flipping a coin on tails is 1/2.  This is because there is one side "tails" out of 2 possibilities.

The probability of rolling a 3 and flipping tails is 1/6(1/2) = 1/12.

P(T|3) = P(3 and Tails)/P(3) = 1/12 / (1/6) = 1/12(6/1) = 6/12 = 1/2

Since P(T|3) = P(3), these are independent events.

3 0
3 years ago
Use the function f(x) = x2 + 6x + 6 and the graph of g(x) to determine the difference between the maximum value of g(x) and the
Bingel [31]

The answer is 15,

because F(X)'s minimum value is (-3, -3)

and G(X)'s maximum value is (12, 3)

So when you subtract -3 from 12, you get a number that is greater then both. (because of the negative 3)

12 - (-3) = 15

5 0
3 years ago
I have a Triangle and I need to find the side BC?
Rus_ich [418]
Looking at this problem in the book, I'm guessing that you've been
introduced to a little bit of trigonometry.  Or at least you've seen the
definitions of the trig functions of angles.

Do you remember the definition of either the sine or the cosine of an angle ?

In a right triangle, the sine of an acute angle is  (opposite side) / (hypotenuse),
and the cosine of an acute angle is (adjacent side) / (hypotenuse).

Maybe you could use one of these to solve this problem, but first you'd need to
make sure that this is a right triangle.

Let's see . . . all three angles in any triangle always add up to 180 degrees.
We know two of the angles in this triangle ... 39 and 51 degrees.
How many degrees are left over for the third angle ?
180 - (39 + 51) = 180 - (90) = 90 degrees for the third angle.
It's a right triangle !  yay !  We can use sine or cosine if we want to.

Let's use the 51° angle.
The cosine of any angle is (adjacent side) / (hypotenuse) .
'BC' is the side adjacent to the 51° angle in the picture,
  and the hypotenuse is 27 .

cosine(51°) = (side BC) / 27

Multiply each side of that equation by 27 :

Side-BC = (27) times cosine(51°)

Look up the cosine of 51° in a book or on your calculator.

Cosine(51°) = 0.62932 (rounded)

<u>Side BC</u> = (27) x (0.62932) = <u>16.992</u> (rounded)
============================================

You could just as easily have used the sine of 39° .
That would be (opposite side) / (hypotenuse) ... also (side-BC) / 27 .
4 0
4 years ago
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