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9966 [12]
3 years ago
7

PLEASE!!!!A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the

function h(t) = −16t2+48t+8. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball's maximum height?
Mathematics
1 answer:
kati45 [8]3 years ago
4 0

Answer:

57ft feet is the answer I think

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Solve for the missing side: simplify the radical ​
Viefleur [7K]

Answer:

x=8\sqrt{5}

Step-by-step explanation:

I will assume the following:

  • You know how to use  the quadratic formula
  • You know how to simplify radicals
  • You know how to use the pythagorean theorem.

The challenge of this exercise comes from using the pythagorean theorem and setting up a few equations.

Given that we have a segment 36 units long and another segment that is 16, it is trivial to get the other segment, 20. Additionally, there are two sides that I want to name so that way I can make a couple of substitutions. I will call these side a and side b. (see attachment 1)

Now comes with setting up three equations. I will start with the two smaller triangles, using side a and side b. See attachments 2 and 3.

Now with the big triangle. I will set up one last equation. See attachment 4.

Given what we know about attachment 2 and 3, we can make two substitutions. See attachment 5. I assume you know how to do the rest and arrive at your only real solution.

5 0
3 years ago
The local radio station is giving away some tickets to the circus. Adult tickets cost $8 each and children's ticket cost $6 each
jeyben [28]
X=22
y=3
Pardon if I am wrong, but all you do is divide 172/8 then divide that by 6. Good Luck.
5 0
3 years ago
The lengths of the two diagonals of a rhombus are 6 cm and 8 cm. Find the length of its perimeter (in
adelina 88 [10]

Answer:

<em>The perimeter of the rhombus is 20 cm</em>

Step-by-step explanation:

<u>Perimeter of a Rhombus</u>

Given the lengths of the two diagonals of a rhombus, let's call them a and b,  the perimeter of the rhombus is given by:

P=2\sqrt{a^2+b^2}

The values of the diagonals provided by the question are a=6 cm, b=8 cm, thus the perimeter is:

P=2\sqrt{6^2+8^2}

P=2\sqrt{36+64}

P=2\sqrt{100}=2*10

P=20\ cm

The perimeter of the rhombus is 20 cm

3 0
3 years ago
You are trying to determine the half-life of a new radioactive element you have isolated. You start with 1 gram, and 5 days late
Oliga [24]
Half-life = elapsed time * log(2) / log (bgng amt / ending amt)
half-life = (5 * <span> <span> <span> 0.3010</span></span></span>3) / log (1/.6)
half-life = (5 * <span> <span> 0.3010</span></span>3) / log (1/.6)
<span>half-life = 1.505 / </span> <span> <span> <span> 0.221848750 </span> </span> </span>
half-life = <span> <span> <span> 6.785 days
Location for formulas & calculator
http://www.1728.org/halflife.htm

</span></span></span>
5 0
4 years ago
Solve the following equation: 0.4(g-2)+1.2=-(g-1)+2.9​
svlad2 [7]
Answer: g = 2.5

Hope it helps!
6 0
3 years ago
Read 2 more answers
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