PLEASE!!!!A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the
function h(t) = −16t2+48t+8. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball's maximum height?
For this case we have the following function: By the time the stone is thrown, x = 0. We must evaluate this value of x in the function. We have then: Answer: The height of the stone at the time is thrown is given by: h (0) = 15 meters