The diameter of a circle is 38 in. What is the circumference of the circle? (Use = 3.14.)

Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x > 0 and y > 0.

morpeh [17]

The first step for solving this expression is to reduce the fraction with 11.
$\sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } }$
Now reduce the fraction with $x^{7}$ .
$\sqrt{ \frac{5 y^{6} }{ x^{4} y^{8} } }$
Reduce the fraction one more time with $y^{6}$ .
$\sqrt{ \frac{5}{ x^{4} y^{2} } }$
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
$\frac{ \sqrt{5} }{ x^{2} y}$
Since we cannot simplify this fraction any further,, the final answer is going to be $\frac{ \sqrt{5} }{ x^{2} y}$ .
Let me know if you have any further questions.
:)

3 0

2 years ago

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11/8 + 3 2/3<br> Solve the problem

Colt1911 [192]

Answer:

121/24 or 5 1/24

Step-by-step explanation:

8 0

2 years ago

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Please help! Will give brainly, 50 points!! I'm stuck with this question and I don't get it!

pishuonlain [190]

Answer: The answer is x^2 + 4x - 3

Step-by-step explanation:

You just combine like terms, the only ones that can combine is the 6x and -4x. You just subtract them to get the answer of x^2 + 4x - 3.

7 0

2 years ago

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For four weeks in June Cameron baked 3 1/4 miles each week and swim 2 1/2 miles each week for three weeks in July he baked 4 3/4

Tems11 [23]

For June:
Bike:
(4) * (3 1/4) = 13 miles
Swim:
(4) * (2 1/2) = 10 miles
Total:
13 + 10 = 23 miles
For July:
Bike:
(3) * (4 3/4) = 14.25 miles
Swim:
(3) * (3 1/2) = 10.5 miles
Total:
14.25 + 10.5 = 24.75 miles
The difference between both months is:
24.75 - 23 = 1.75 miles
Answer:
the total distance Cameron bike and swim in July compared to the total distance he bike in swim in June was 1.75 miles greater

6 0

2 years ago

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions:y >

pantera1 [17]

Answer:

Part A: The graph of given inequality is shown below.

Part B: The point (4,6) is not a solution of given system of inequalities.

Step-by-step explanation:

Part A:

The given inequalities are

$y>2x+3$

$y$

The related equation of given inequalities are

$y=2x+3$

$y=-\frac{3}{2}x-4$

Put x=0, to find the y-intercepts.

$y=2(0)+3=3$

$y=-\frac{3}{2}(0)-4=-4$

Put y=0, to find the x-intercepts.

$0=2x+3\Rightarrow x=-\frac{3}{2}$

$0=-\frac{3}{2}x-4\Rightarrow x=-\frac{8}{3}$

The x and y-intercepts of first line are (0,3) and (-1.5,0) respectively. The x and y-intercepts of second line are (0,-4) and (-2.667,0) respectively.

Check the given inequality by (0,0).

$0>2(0)+3$