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Crazy boy [7]
3 years ago
9

Help me out really fast please

Mathematics
2 answers:
laiz [17]3 years ago
8 0

Answer: Use the same counter weight.

Step-by-step explanation: It should be the controlled variable whereas the ball would be the independent, and the distance the dependent.

Bumek [7]3 years ago
6 0

Answer:

it would be D.

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Completa el enunciado siguiente. Luego usa una recta numérica para hallar la suma 4 + (-7).
bagirrra123 [75]
Respuesta Es -3 (tried my best I’m only in Spanish two my main language is English)
8 0
3 years ago
What is the solution to the system of equations? Use the substitution method. {y=−2x+53x−4y=2
klio [65]

y =  - 2x + 53x - 4y = 2 \\  y  = 51x - 4y = 2 \\  > y = 51 x - 4y \\  > 51x - 4y = 2
y = 51x - 4y \\ 5y = 51x \\ y =  \frac{51}{5} x
Substitute 51/5x into
51x - 4( \frac{51}{5} x) = 2 \\ 51x - 40.8x = 2 \\ 10.2x = 2 \\ x = 2 \times  \frac{10}{102}  \\ x =  \frac{10}{51}  \: aka \: 0.196
Substitute that into
y =  \frac{51}{5}  \times  \frac{10}{51}  \\ y = 2
Hope this helps. Answer should be correct. Unless your quadratic equation is wrongly stated.
8 0
3 years ago
Aanand earns Rs 80 in 7 hours and pramode earns Rs 90 in 12 hours. find their ratio​
My name is Ann [436]

Answer:

1.671:1

Step-by-step explanation:

80/7=11.99(9) or ~12

90/12= 7.177(7)

11.99(9)/7.177(7)=1.671

1.671:1

6 0
4 years ago
Which of the following possibilities will form a triangle?
s2008m [1.1K]

Answer:

D

Step-by-step explanation:

Triangle Side Theorem: The two smaller sides of a triangle

must be greater than the largest side

8 + 9 > 16

6 0
3 years ago
How many 4 digit numbers consisting of only the digits 2,4,6 and 8 are divisible by 4
Blababa [14]

Answer:

  • digits used once: 12
  • repeated digits: 128

Step-by-step explanation:

In order for a number to be divisible by 4, its last two digits must be divisible by 4. This will be the case if either of these conditions holds:

  • the ones digit is an even multiple of 2, and the tens digit is even
  • the ones digit is an odd multiple of 2, and the tens digit is odd.

We must count the ways these conditions can be met with the given digits.

__

Since we only have even numbers to work with, the ones digit must be an even multiple of 2: 4 or 8. (The tens digit cannot be odd.) The digits 4 and 8 comprise half of the available digits, so half of all possible numbers made from these digits will be divisible by 4.

<h3>digits used once</h3>

If the numbers must use each digit exactly once, there will be 4! = 24 of them. 24/2 = 12 of these 4-digit numbers will be divisible by 4.

<h3>repeated digits</h3>

Each of the four digits can have any of four values, so there will be 4^4 = 256 possible 4-digit numbers. Of these, 256/2 = 128 will be divisible by 4.

7 0
2 years ago
Read 2 more answers
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