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3 years ago

Can you help me! ln this question .and explain it in step by step (optional math)

Mathematics

1 answer:

photoshop1234 [79]3 years ago

8 0

Answer:

$\frac{6}{ \sqrt{3 } } - 2 \sqrt{2} - \frac{5 \sqrt{3} }{4} = 6 - 2 \sqrt{6} - \frac{15}{4} = \frac{9}{4} - 2 \sqrt{6}$

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The rule below shows how to find the position of an object thrown upward with initial velocity of 15 feet per second. Which answ

nekit [7.7K]

Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.

This rule has the form

h(t) = h + v t + (1/2)a*t^2

o o

To adapt this rule to this particular question replace h with 0, as the

upward path of the object begins at 0 ft. Replace v with +15 ft/sec.

Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.

Then we have the following, with the label F(t):

F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or

F(t) = 15t - 16.1t^2. Thus, Choice D is correct.

Please note: To avoid confusion, please use " ^ " to denote exponentiation:

F(t) = -16t^2 + 15t

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4 years ago

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Zina [86]

Answer:

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3 years ago

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

l denotes length
b denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

Therefore, length and breadth of the rectangle is 15 m and 10 m. 

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3 years ago

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aleksklad [387]

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Can you help me! ln this question .and explain it in step by step​ (optional math)

Can you help me! ln this question .and explain it in step by step (optional math)