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mars1129 [50]
3 years ago
7

Use the coordinates of the labeled point to find a point-slope equation of the

Mathematics
1 answer:
nataly862011 [7]3 years ago
6 0

Answer:

dw

Step-by-step explanation:

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X=120 mark as brainliest of correct
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Ughhhh helllppp? Thanks...
True [87]
Hello there! I can help you! So in this question, we are talking about an elephant eating 400 pounds each day. Knowing this can help us solve these questions:

a. So v represents number of pounds and d represents the number of days. We would write the equation as v = 400d, because you multiply the amount of days and pounds eaten per day to find the total amount of vegetation the animal has ate.

b. So given the equation, all we have to do is plug in a number for d and multiply to find v. Let's find the value for 3 days, starting with day 1. 400 * 1 is 400. 400 pounds eaten in day 1. 2 * 400 is 800. 800 total pounds eaten on day 2. 3 * 400 is 1,200. 1,200 total pounds eaten on day 3. With those numbers, your table should look like the one below if you do it correctly.

c. With that, your points should be placed at (1, 200), (2, 800), (3, 1,200). You can see that the line is constant, and that when you connect the dots, the line is straight. It is a linear equation, where the line is straight and the value is constant.

5 0
3 years ago
11 ounces of tomato soup has 70 calories. How many calories are in 22<br> ounces of soup? *
fenix001 [56]

Answer:

140 ounces

Step-by-step explanation:

We use ratio and proportion.

\frac{11}{22} =\frac{70}{x}

Cross multiply, and you get:

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How do I find the Velocity and How long will it take for the ball to reach it's maximum height?
Colt1911 [192]
So hmm check the picture below

\bf \qquad \textit{initial velocity}\\\\&#10;h = -16t^2+v_ot+h_o \qquad \text{in feet}\\&#10;\\ &#10;\begin{cases}&#10;v_o=\textit{initial velocity of the object}\to &64\\&#10;h_o=\textit{initial height of the object}\to &12\\&#10;h=\textit{height of the object at "t" seconds} \end{cases}\\\\&#10;-----------------------------\\\\

\bf \textit{vertex of a parabola}\\ \quad \\&#10;&#10;\begin{array}{lccclll}&#10;h(t)=&-16t^2&+64t&+12\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array}\qquad &#10;\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

part 1)  

it takes  \bf -\cfrac{{{ b}}}{2{{ a}}}\quad seconds

part 2)

\bf \textit{now, doubling }v_o\\\\&#10;\begin{cases}&#10;v_o=\textit{initial velocity of the object}\to &128\\&#10;h_o=\textit{initial height of the object}\to &12\\&#10;h=\textit{height of the object at "t" seconds}\end{cases}\\\\&#10;-----------------------------\\\\&#10;\textit{vertex of a parabola}\\ \quad \\&#10;&#10;\begin{array}{lccclll}&#10;h(t)=&-16t^2&+128t&+12\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array}\qquad &#10;\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

it will reach the maximum height at   \bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\quad feet


how much higher than before is that? well, what was the y-coordinate for when the vₒ was 64? what did you get for \bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}} ?

subtract that from this height when vₒ is 128 or doubled, to get their difference, that's how much higher it became

4 0
3 years ago
GUIDE QUESTIONS:
maria [59]

Answer:

1.sowwy I dunno

2.its so good and it's perfect

3.i dunno ulet hehe

Step-by-step explanation:

Sorry walang matino na sagot.

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