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Vera_Pavlovna [14]
3 years ago
13

What is 5 + 5 + 5 + 5 + 6 + 7 + 5 + 6 + 4 + 4+ 4 + 6+ 3 + 3 + 1 + 9?

Mathematics
2 answers:
cupoosta [38]3 years ago
8 0

Answer:

78

Step-by-step explanation:

elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

5,555,675,644,463,319

Step-by-step explanation:

plz mark brainly

                                                         JK 78 LOL

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What does distributions from owners int non adr mean?
Bond [772]
Distributions from owners are earnings that an owner withdraws from a business based on the profit that the company has made. It is payed in the form of a dividend. ADR stands for American Depositary receipt. ADR <span>is a stock that trades in the United States and represents a specified number of shares in a foreign corporation. So, the payment that the owner will get will not be from the ADR stock.</span><span>

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5 0
3 years ago
Samantha works at a nursery, where she pots plants. it takes her 1 1/2 hours to pot 12 plants.
nignag [31]

Answer:

She could plant 9 plants.

Step-by-step explanation:

1 1/2 hours = 90 minutes, so 12 plants per 90 minutes. Which would mean 6 plants per 45 minutes. So in between 45 and 90 minutes (1 hour), and in between 6 and 12 plants (9).

Sorry if you didn't understand, I'm bad at explaining.

4 0
2 years ago
What is .16÷.03220 round to the nearest tenth? ​
Alika [10]

Answer:

5.0 would be your answer.

Have a great day/night!

6 0
3 years ago
Choose the equation below whose axis of symmetry is x = 2.
soldi70 [24.7K]

Answer:

y= x^2 - 4x + 2

I did the test I got it right!

Hope it helps.

5 0
3 years ago
Read 2 more answers
A particle in the first quadrant is moving along a path described by the equation LaTeX: x^2+xy+2y^2=16x 2 + x y + 2 y 2 = 16 su
ElenaW [278]

Answer:

\frac{50}{3} cm/sec.

Step-by-step explanation:

We have been given that a particle in the first quadrant is moving along a path described by the equation x^2+xy+2y^2=16 such that at the moment its x-coordinate is 2, its y-coordinate is decreasing at a rate of 10 cm/sec. We are asked to find the rate at which x-coordinate is changing at that time.

First of all, we will find the y value, when x =2 by substituting x =2 in our given equation.

2^2+2y+2y^2=16

4-16+2y+2y^2=16-16

2y^2+2y-12=0

y^2+y-6=0

y^2+3y-2y-6=0  

(y+3)(y-2)=0

(y+3)=0,(y-2)=0

y=-3,y=2

Since the particle is moving in the 1st quadrant, so the value of y will be positive that is y=2.

Now, we will find the derivative of our given equation.

2x\cdot x'+x'y+xy'+4y\cdot y'=0

We have been given that y=2, x =2 and y'=-10.

2(2)\cdot x'+(2)x'+2(-10)+4(2)\cdot (-10)=0

4\cdot x'+2x'-20-80=0

6x'-100=0

6x'-100+100=0+100

6x'=100

\frac{6x'}{6}=\frac{100}{6}

x'=\frac{50}{3}

Therefore, the x-coordinate is increasing at a rate of \frac{50}{3} cm/sec.

7 0
3 years ago
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