The provided equation is not an identity
C is the answer.
We multiply the top and bottom of this by the conjugate (switch the sign of the square root):
(2-sqrt8)(4-sqrt12)/(4+sqrt12)(4-sqrt12)
Multiying the top we have
8-2sqrt12-4sqrt8+sqrt(8×12)
Multiplying the bottom we have:
16-4sqrt12+4sqrt12-12
On top, we simplify the radicals and get
8-4sqrt3-8sqrt2+4sqrt6
On bottom, we have
16-12=4
Now we divide everything on top by 4 and get
2-sqrt3-2sqrt2+sqrt6
I believe it should be constant since the line has a slope of 0
Answer:
1. Exponential
Step-by-step explanation:
The simplest RC-Circuit, that is, a capacitor and a resistor in a series configuration can be modeled by using Ohm's Law and Kirchhoff's Circuit Laws:
By rearranging the formula, an homogeneous linear first-order differential equation is found:
Whose solution has the form of a exponential model:
Answer:
BABY YODA= GOD
Step-by-step explanation:
