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frosja888 [35]
3 years ago
5

.3 ovos .60 gramas de manteiga

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0

Answer:

english please

Step-by-step explanation

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For each of the following shapes, state whether or not it has reflection symmetry. If it does , draw the lines of symmetry it.
Effectus [21]
You would have to draw a line across
5 0
2 years ago
In which number does the digit 4 have a value that is \dfrac{1}{10} 10 1 ​ start fraction, 1, divided by, 10, end fraction times
MrRissso [65]

Answer:

The digit 4 should be in the thousand position in the number sought;

Examples  

9.30<u>4</u>,

9.00<u>4</u>

Step-by-step explanation:

Here, we are required to consider decimal places of numbers

The digit 4 in the number 3.8463 is in the hundredth position

That is 0.04

We are asked to look for the number with a digit 4 that has the same value as \frac{1}{10} \times the digit 4 in 3.8463

That is

\frac{1}{10}  \times 0.04 = 0.004

Therefore, the digit 4 in the number sought should be in the thousandth position, that is 0.004

Example includes 9.304 or 9.004.

4 0
3 years ago
Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are
Svetlanka [38]

Answer:

(a) Number of sets B given that

  • A⊆B⊆C: 2¹⁰.  (That is: A is a subset of B, B is a subset of C. B might be equal to C)
  • A⊂B⊂C: 2¹⁰ - 2.  (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

<h3>(a)</h3>

Let x_1, x_2, \cdots, x_{20} denote the 20 elements of set X.

Let x_1, x_2, \cdots, x_{10} denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain x_1, x_2, \cdots, x_{10}.

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from x_1, x_2, \cdots, x_{20}.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves 2^{10} -2 = 1024 - 2 = 1022 possibilities.

<h3>(b)</h3>

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's 2^{20} = 1048576 possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only 2^{20} - 2^{10} possibilities left.

5 0
3 years ago
5. Car rental company A charges $30 a days and
olga nikolaevna [1]

Answer:

Step-by-step explanation:

I need  the answer for same question pleas

5 0
4 years ago
Read 2 more answers
Can you guys please help me my math teacher wants us to get this right and I don’t get it please help me on all of it
Ostrovityanka [42]

#5 is

Let's solve your equation step-by-step.

2

5

x−1=9

Step 1: Add 1 to both sides.

2

5

x−1+1=9+1

2

5

x=10

Step 2: Multiply both sides by 5/2.

(

5

2

)*(

2

5

x)=(

5

2

)*(10)

x=25

Answer:

x=25

7 0
3 years ago
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