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AysviL [449]
3 years ago
9

Just please help help help help

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

C.{(-3,10),(-2,5),(1,2),(-2,-4)}

You might be interested in
The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.
slamgirl [31]

Answer:

b=-6\\c=7

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}

substitute

y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Applying the distributive property convert to expanded form

y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})

y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)

y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7

y=x^2-6x+7

therefore

b=-6\\c=7

7 0
3 years ago
Anyone know 14!!!! ASAP
notsponge [240]
Word problem: Today the temperature dropped 13 °F. After this drop, the temperature was 74 °F. What was the original temperature outside before the drop?

Subtraction problem: x °F - 13 °F = 74 °F

Solve: x - 13 = 74
x - 13(+13) = 74 + 13
x = 87 °F
3 0
4 years ago
Pythagoras Theorem and Quadratic Equations<br> Solve for x:<br> a= (x-2)<br> b= 9<br> c= (x+1)
Alex_Xolod [135]

Answer:

Step-by-step explanation:

Pythagoras theorem

a^2=b^2+c^2

(x-2)^2=9^2+(x+1)^2

x^2-4x+4=81+x^2+2x+1

Collect like terms

-4x-2x=82-4

-6x=78

x=-13

3 0
3 years ago
Read 2 more answers
-2=___+6<br> Fill in the blank!
Drupady [299]

Answer:

<h2>-8   +6=-2  </h2>

it took me a while, but yeah....

hope im right, and i really hope this helps.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
To
jolli1 [7]

Answer:

6

Step-by-step explanation:

3 0
3 years ago
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