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AysviL [449]
3 years ago
9

Just please help help help help

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

C.{(-3,10),(-2,5),(1,2),(-2,-4)}

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Question 1<br> 2 (4x - 1) + 6<br> Equivalent to what
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Answer:

2 (4x - 1) + 6 = 8x + 4 = 4(2x+1)

Step-by-step explanation:

2 (4x - 1) + 6

= (2*4x + 2*-1) + 6

= 8x - 2 + 6

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= 4/(2x+1)

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3 years ago
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Please answer asap its due today
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rdh

Step-by-step explanation:

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3 years ago
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\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad &#10;\begin{cases}&#10;63=3\cdot 3\cdot 7\\&#10;6=2\cdot 3&#10;\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\&#10;\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
3 years ago
What does 4x+7x equal ?
olganol [36]

Answer:

11x

Step-by-step explanation:

u just add them regularly

7 0
3 years ago
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