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suter [353]
2 years ago
15

Identify the variable and the constant in the expression below. n + 3 variable: ___________________________ constant: __________

_________________
Mathematics
1 answer:
Ilya [14]2 years ago
8 0
N is the variable and 3 is the constant.
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Select the best answer for the question. 17. 18 is what percent of 20? A. 10% B. 90% C. 18% D. 95%
vovangra [49]
Percent formula : is/of = %/100

18 is what percent of 20...
is = 18
of = 20
% = x

sub and solve
18/20 = x/100
cross multiply
(20)(x) = (100)(18)
20x = 1800
x = 1800/20
x = 90 <=== so 18 is 90% of 20
8 0
3 years ago
Read 2 more answers
Evaluate the expression when y=-2.<br> y2 +6y-4
vaieri [72.5K]

Answer:-12

Step-by-step explanation:

6 0
3 years ago
Neep help pls, what is the answer????
saveliy_v [14]

Answer:

No, According to triangle Inequality theorem.

Step-by-step explanation:

Given:

Length given are 4 in., 5 in., 1 in.

We need to check whether with these lengths we can create triangular components.

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

These must be valid for all three sides.

Hence we will check for all three side,

4 in + 5 in > 1 in. (It is a Valid Condition)

1 in + 5 in > 4 in. (It is a Valid Condition)

4 in + 1 in > 5 in. (It is not a Valid Condition)

Since 2 condition are valid and 1 condition is not we can say;

A triangular component cannot be created with length 4 in, 5 in, and 1 in by using triangle inequality theorem (since all three conditions must be valid).

6 0
2 years ago
The sum of two numbers is -26. One number is 148 less than the other. Find the numbers
maks197457 [2]

Answer:

61 and -87

Step-by-step explanation:

If the numbers are x and x - 148, we can write the following equation:

x + x - 148 = -26

2x - 148 = -26

2x = 122

x = 61 so x - 148 = 61 - 148 = -87

5 0
3 years ago
Name all of the sets to which the real number 60 belongs
liberstina [14]
Natural, Whole, and Integers. Hopefully I helped :)
5 0
3 years ago
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