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solniwko [45]
3 years ago
13

You made Marcellus 3 times as tall as Dan but you dragged Marcellus’s mouth to be 5.46 times as wide as Dan’s mouth. A proportio

nal giant would have the same multiple for both.
If Dan's mouth is 4 cm wide, how many centimeters wide should Marcellus's mouth be?
Mathematics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

22.34 cm wide

Step-by-step explanation:

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Write the rules for determining the sign of the product when multiplying integers. Then, write (4 points)
borishaifa [10]

While multiplying a negative and another negative integer, the product's will be positive. While multiplying a positive and another positive integer, the product will be positive. It means that of the integers have same sign, then their product's sign will be positive. But, if the integers have different signs, i.e., one of them is positive and the other is negative, then the product will have negative sign.

While dividing a negative from another negative integer, the quotient will be positive. While dividing a positive from another positive integer, the quotient will be positive. It means that of the integers have same sign, then their quotient's sign will be positive. But, if the integers have different signs, i.e., one of them is positive and the other is negative, then the quotient will have negative sign.

6 0
3 years ago
Read 2 more answers
A researcher drilled a hole in a die and filled it with a lead​ weight, then proceeded to roll it 209 times. The observed freque
ddd [48]

Answer:

Step-by-step explanation:

Given that the observed frequencies for the outcomes as follows:

To check this we can use chi square goodness of fit test.

H_0: equally likely\\H_a: not equally likely

(Two tailed test at 5% significance level)

Assuming equally likely expected observations are found out and then chi square is calculated as (0-E)^2/E

Df = 6-1 =5

Outcome Frequency Expected frequency (Obs-exp)^2/Exp

   

1 36 34.83333333 0.03907496

2 30 34.83333333 0.670653907

3 41 34.83333333 1.091706539

4 40 34.83333333 0.766347687

5 23 34.83333333 4.019936204

6 39 34.83333333 0.498405104

   

209 209          7.086124402

p value =0.214

Since p >alpha, we accept null hypothesis

It appears that the  loaded die does not behave differently than a fair​ die at 5% level of significance

5 0
3 years ago
Please help me with this Statistics problem
Cerrena [4.2K]
It would be the first answer. Bubble. I don't know what you call it. But yeah, it's the first one.
7 0
3 years ago
At a local print shop, 18 copies can be made for $6. At this rate, how much would it
Ber [7]

Answer: to make 78 copies it cost 26 dollars.

Step-by-step explanation:

18 copies - 6 dollars

78 copies - x dollars

Hence,

\displaystyle\\x=\frac{78*6}{18} \\\\x=\frac{26*3*6}{3*6} \\\\x=26 \ dollars

5 0
2 years ago
Of the Students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of th
soldier1979 [14.2K]

Answer:

\frac{9}{20} students.

Step-by-step explanation:

We have been given that of the students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of the students are also involved in the drama club.

To find the students are both play a sport and a part of the drama club, we need to find 3/5 part of 6/8 as:

\text{Students who play a sport and a part of the drama club}=\frac{6}{8}\times \frac{3}{5}

\text{Students who play a sport and a part of the drama club}=\frac{3}{4}\times \frac{3}{5}

\text{Students who play a sport and a part of the drama club}=\frac{3\times 3}{4\times 5}

\text{Students who play a sport and a part of the drama club}=\frac{9}{20}

Therefore, \frac{9}{20} students play sport and part of the drama club.

5 0
3 years ago
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