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solniwko [45]
4 years ago
12

Choose the correct simplification of the expression (4a4b)2. 16a8b 16a8b2 16a6b2 8a8b2

Mathematics
2 answers:
iogann1982 [59]4 years ago
5 0

Given exponential expression : (4a^4b)^2.

<em>According to exponents of exponent rule, we need to distribute whole exponent over exponents of inside terms of parenthesis.</em>

We are given whole exponent 2 there.

We can apply exponents of exponent rule.

Therefore,

(4a^4b)^2 = 4^2 a^{4\times2}b^2

4^2= 16.

a^{4\times2} = a^8

Therefore, 4^2 a^{4\times2}b^2 = 16a^8b^2.

<h3>Correct option is second option 16a^8b^2.</h3>
Korolek [52]4 years ago
4 0

Answer:

BBBBBBBBBBBBBBBBBBBBBBBBBBBB

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Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

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A triangle has side lengths measuring 20 cm, 5 cm, and n cm. Which describes the possible values of n? 5 &lt; n &lt; 15 5 &lt; n
ehidna [41]

Answer:

15 < n < 25

Step-by-step explanation:

According to the triangle inequality theorem, any two sides lengths' sum should be greater than the third side. This also implies that to find the <em>possible length of  the 3rd side given other two sides (let two given sides be x and y)</em>, we can say that the 3rd side length will be between x+y and x-y.

Hence, we can say that <em><u>n should be between 20+5 and 20-5</u></em>.

So, 20 - 5 < n < 20 + 5, which is

15 < n < 25

<em>This is the correct answer.</em>

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