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gtnhenbr [62]
3 years ago
14

Find the probability of rolling a 4 or less on the first die, and a 5 or less on the second die

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

first dice-4/6

second dice-5/6

Step-by-step explanation:

if you have six possible outcomes for the first dice and you want it to roll 1 thru 4 then you have a four out of six chance and you have a 5 out of six chance for the second dice

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Solve for k.<br> 8(10 - k) = 2
scoundrel [369]

Answer:

k= 39/4; k = 9.75; k= 9  3/4

Step-by-step explanation:

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Fran is making a punch for her birthday party. She needs 4 1/5 liters of juice for the punch, but she only has 1 4/5 liters. How
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Answer: she needs 2 2/5 liters

Step-by-step explanation:

5 0
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Read 2 more answers
What does this mean 31&gt;28
Alona [7]

Answer:

31 is greater than 28

Step-by-step explanation:

That is how you read it: 31 is greater than 28

8 0
3 years ago
Read 2 more answers
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
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