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kykrilka [37]
3 years ago
14

Please help me with these two problems thank you!!​

Mathematics
1 answer:
andriy [413]3 years ago
8 0

Answer:

1st question: y=1/3x-1

2nd question: y=-2/3x+9

Step-by-step explanation:

Y=mx+b form is what you are using

when a line in parallel to a line they have the same slop wich is m

when a line in perpendicular they have the opposite reciprocal

Examples: 2/5 opposite reciprocal would be -5/2

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2000:$5 2015:$6.5 what is the percent change
Julli [10]

Answer:

30%

Step-by-step explanation:

% of change = 100 x (6.5-5)/  | 5 |

7 0
3 years ago
What is 4% of 40 as a percent
Ilia_Sergeevich [38]
<span><span>1/10=10%
</span><span>2/10=20%
</span><span>3/10=30%
</span><span>4/10=<span>40%
does this help</span></span></span>
3 0
3 years ago
Read 2 more answers
Which table contains only corresponding x-values and y-values where the value of y is 3 more than the quotient of x and 2
Readme [11.4K]
Y=3+x/2 all u had to do is write the equation out 
7 0
3 years ago
Let a represent the number of ounces of perfume A. Let b represent the number of ounces of perfume B. Perfume A costs $11 per ou
Julli [10]

Answer:

The system of equations in standard form is equal to

11a+19b=71

a+b=5

The number of ounces of perfume A is 3\ ounces

The number of ounces of perfume B is 2\ ounces

Step-by-step explanation:

Let

a-----> the number of ounces of perfume A

b----> the number of ounces of perfume B

we know that

11a+19b=71 -----> equation A

a+b=5

a=5-b -----> equation B

substitute equation B in equation A and solve for b

11(5-b)+19b=71

55-11b+19b=71

8b=71-55

8b=16

b=2\ ounces

Find the value of a

a=5-b -----> a=5-2=3\ ounces

8 0
3 years ago
Read 2 more answers
Suppose a population of deer in the state is 10, 289 and is growing 1% each year. Predict the population after 5 years
eimsori [14]

Answer: the population after 5 years is 10814

Step-by-step explanation:

The population growth of the deer is exponential. We would apply the formula for determining exponential growth which is expressed as

A = P(1 + r)^t

Where

A represents the population after t years.

n represents the period of growth

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 10289

r = 1% = 1/100 = 0.01,

t = 5 years

Therefore,

A = 10289(1 + 0.01)^5

A = 10289(1.01)^5

A = 10814

3 0
4 years ago
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