Answer:
Left: x = 56
Right: x = 58 1/2
Step-by-step explanation:
The <em>inscribed angle theorem </em>says that the inscribed angle subtended by an arc is half the measure of the central angle subtended by that same arc. In other words, if we had an arc with a measure of 12 degrees, its corresponding inscribed angle would be exactly 6 degrees, and if we had an inscribed angle measuring 10 degrees, it would be subtend an arc measuring 20 degrees.
On the left, we're given a measure of 28 degrees for the inscribed angle and have to find the measure of x, the subtended arc. Since 28 has to be half of x by the inscribed angle theorem, x must be 28 x 2 = 56°
On the right, we're given an arc with a measure of 117°, and we have to find the measure x° of the inscribed angle. Of course, this angle must be half of 117, so x = 117/2 = 58 1/2.
1x+ 3y = -12x + 2y = 6
+12x +12x
13x + 3y = 2y = 6
+3y +3y
13x = 5y = 6
13x = 5y and 5y = 6
Answer:
93
Step-by-step explanation:
Key :
A1 = Algebra 1
A2 = Algebra 2
Alright so basically lets first look at the info they gave us :
We have 5 more than twice as many students taking A1 than we do A2.
We have 44 students taking A2.
And we need to find the least amount of students that could be taking A1.
So we need to take the amount of students taking A2 (44) and double it to find the amount taking A1.
So we can do 44 x 2 = 88 to get this.
But the problem also states there is 5 more then twice the number of students taking A2.
So we have that 88 but now we just need to add 5 to make up for them telling us that in the problem.
So :
88 + 5 = 93
Our final answer and least amount of students taking A1 is 93 students.
Answer:
19
Step-by-step explanation:
3 to the power of 2 is 9
5 times 2 is 10
10 plus 9 is 19
Answer:
The answer is volume!!!!!
Step-by-step explanation:
i have the same exact question. Hope this helps!!! :)
