ANSWER
A) -1
EXPLANATION
The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).
That is the average rate of change is:
From the graph, f(0) is 0 and f(4) is -4.
We plug in these values to obtain;
This simplifies to;
Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1
Answer:
Look down!!
Step-by-step explanation:
Since two points determine any line, we can graph lines using the x- and y-intercepts. To find the x-intercept, set y = 0 and solve for x. To find the y-intercept, set x = 0 and solve for y. This method of finding x- and y-intercepts will be used throughout our study of algebra because it works for any equation.
Ex.
4=2+2
y=4
x=2
Hope this helps!!
Hi there!
The question gives us the quadratic equation , and it tells us to solve it using the quadratic formula, which goes as . However, we must first find the values of a, b, and c. The official quadratic equation goes as , which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation.
x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}
x = \frac{-(5) \pm \sqrt{(5)^2 - 4(1)(3)} }{2(1)}
x = \frac{-5 \pm \sqrt{25 - 12} }{2}
x = \frac{-5 \pm \sqrt{13} }{2}
x = \frac{-5 \pm 3.61 }{2}
x = \frac{-5 + 3.61 }{2}, x = \frac{-5 - 3.61 }{2}
x=-0.695 \ \textgreater \ \ \textgreater \ -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31
Therefore, the solutions to the quadratic equation are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!
Your answer is 4.31
Answer: B. Triangle
Step-by-step explanation:
The vertical cross-section of a pyramid is a triangle, and the horizontal cross-section of a pyramid is a square.
Answer:
6.4/7.7 is the ratio
Step-by-step explanation:
The bottom triangle matches the 50 40 90 angle, so the ratio of the triangle length is consistent
- Gage Millar, Algebra 2 tutor
