Answer:
B,C,E are right statements
1. You have that:
- The<span> lengths of the bases are (6x-1) units and 3 units.
- The midsegment has a length of (5x-3) units.
2. To solve this exercise, you must apply the formula for calculate the length of the midsegment of a trapezoid, which is shown below:
Midsegment=Base1+Base2/2
As you can see, the midsegment is half the sum of the bases of the trapezoid.
3. When you substitute the values, you obtain:
(5x-3)=[(6x-1)+3]/2
4. Now, you can solve the problem by clearing the "x":
</span>
(5x-3)=[(6x-1)+3]/2
2(5x-3)=6x-1+3
10x-6=6x+2
10x-6x=2+6
4x=8
x=8/4
x=2
Answer/Step-by-step explanation:
✔️Find EC using Cosine Rule:
EC² = DC² + DE² - 2*DC*DE*cos(D)
EC² = 27² + 14² - 2*27*14*cos(32)
EC² = 925 - 756*cos(32)
EC² = 283.875639
EC = √283.875639
EC = 16.85 cm
✔️Find the area of ∆DCE:
Area = ½*14*27*sin(32)
Area of ∆DCE = 100.15 cm²
✔️Since ∆DCE and ∆ABE are congruent, therefore,
Area of ∆ABE = 100.15 cm²
✔️Find the area of the sector:
Area of sector = 105/360*π*16.85²
Area = 260.16 cm² (nearest tenth)
✔️Therefore,
Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)
These are the steps. Just follow the numbers on the left hand side. Hopes this helps. The answer is -3.
