In reducing one's speed from 70 mph to 50 mph, how much of a percentage decrease in stopping distance is realized (to the neares

Question

3 years ago

6

t percent)?

1 answer:

labwork [276] · Answer 1 · 2022-01-19T00:28:57+03:00

6 0

we are given

we are given relation between speed and distance

distance ( when speed =70mph) is

=328feet

so, $d_1=328$

distance ( when speed =50mph) is

=183feet

so, $d_2=183$

now, we can find percentage in decrease

$=\frac{d_1-d_2}{d_1} \times 100$

now, we can plug values

$=\frac{328-183}{328} \times 100$

$=44$ %...........Answer