The value of f(h(2)) =2 and h(f(16))= 14
<h3>What is function?</h3>
Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input . Mapping or transformation is used to denote a function in math. These functions are usually denoted by letters . The domain is defined as the set of all the values that the function can input while it can be defined. The range is all the values that come out as the output of the function involved.
given:
f(x)= √x-1 , h(x)= x² + 5
Now,
f(h(2))= f( (2)² +5 )
=f(4+5)
=f(9)
=√9-1
= 3-1
=2
h(f(16)) = h( √16-1)
=h( 4-1)
=h(3)
=3² + 5
=9+5
=14
Learn more about function here:
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X + y = 4...x = 4 - y
2x + 3y = 0
2(4-y) + 3y = 0
8 - 2y + 3y = 0
-2y + 3y = 0 - 8
y = -8
x + y = 4
x - 8 = 4
x = 4 + 8
x = 12
solution is : (12,-8)
Answer:
B. √21
Step-by-step explanation:
x^2 = √5 x √5 + 4 x 4
x^2 = 5 + 16
x^2 = 21
x = √21
<em>Hope that helps! :)</em>
<em></em>
<em>-Aphrodite</em>
Given
Divide it by (x+1) using synthetic division, as shown below
The green line is a minus sign.
Thus,
Therefore, since the remainder is different than zero, (x+1) is not a factor of 4x^2+2x-5
