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3 years ago

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Suppose a merry-go-round is spinning once every 3 seconds. If a point on the outside edge has a speed of 12.56 feet per second,

what is the radius of the merry-go-round? (Use 3.14 for pi)

1 answer:

Vladimir79 [104]3 years ago

4 0

all you have do is divide 3.14 by 3 which =1.04

ANSWER =1.04

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You work at an ice-cream shop. One of your jobs is to order new ice-cream cones. You pick the cone that is 5 inches high and has

Taya2010 [7]

We have that
the Volume of cone=(1/3)*B*h
B=the area of the base
h= the height of the cone
D=3.5 in-----------------> r=D/2=1.75 in
h=5 in
B=pi*r²---------> 3.14*1.75²=9.616 in²
V=(1/3)*9.616*5=48.08 in³--------> 48 in³

the answer is 48 in³

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k0ka [10]

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vekshin1

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3 years ago

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melamori03 [73]

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Step-by-step explanation:

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Leokris [45]

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