Answer:
The total surface area of this square pyramid is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to
![SA=b^{2} +4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have
----> the length side of the square base
----> the height of the triangular faces
substitute the values
![SA=9^{2} +4[\frac{1}{2}(9)(12)]=297\ mm^{2}](https://tex.z-dn.net/?f=SA%3D9%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%289%29%2812%29%5D%3D297%5C%20mm%5E%7B2%7D)
The slope intercept form is y=mx+b. m is the slope, b is the y intercept,
What are the ordered pairs
-2(-5)^2 + 7
-2 • 5^2 + 7
-2 • 25 + 7
-50 + 7
-43
Answer:
z = -1
Step-by-step explanation:
7 - z / -2 - (-1)
7 - z / -2+1
7 - z / -1
-7 +z = -8
z = -1
to check the work
(-1,-1) (-2,7)
7 + 1 / -2 + 1
8 / -1
= -8
