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Minchanka [31]
3 years ago
13

Suppose a merry-go-round is spinning once every 3 seconds. If a point on the outside edge has a speed of 12.56 feet per second,

what is the radius of the merry-go-round? (Use 3.14 for pi)
Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

all you have do is divide 3.14 by 3 which =1.04

ANSWER =1.04

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The link has a visual of vertical angles.

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https://www.mathsisfun.com/geometry/adjacent-angles.html
The link has a visual of adjacent angles.

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