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Dafna11 [192]
2 years ago
5

PLEASE ANSWER QUICKLY

Mathematics
1 answer:
wel2 years ago
6 0

Answer:

65 passengers

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Classify the limaçon represented by the equation r=(1/2)-(1/2)sin(theta)
babunello [35]
We know that

Limacons are in the form
r=a(+-)b*sin (theta)  or r=a(+-)b*cos (theta)

in this problem
r=a(+-)b*sin (theta)
so
is symmetric to y axis
a=1/2
b=1/2
a/b=1---------> Cardioid (hearth shaped)

see the attached figure

the answer is the option
<span>A. Cardioid </span>

4 0
3 years ago
Solve the equation
inysia [295]

Answer:

x ≈ 1.32, x ≈ - 5.32

Step-by-step explanation:

Given

x² + 4x - 7 = 0 ( add 7 to both sides )

x² + 4x = 7

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 7 + 4

(x + 2)² = 11 ( take the square root of both sides )

x + 2 = ± \sqrt11} ( subtract 2 from both sides )

x = - 2 ± \sqrt{11}

Thus

x = - 2 - \sqrt{11} ≈ - 5.32 ( to 2 dec. places )

x = - 2 + \sqrt{11} ≈ 1.32 ( to 2 dec. places )

8 0
3 years ago
Read 2 more answers
On the distant plant, Mathology, a sports area covers 7400 yodels2. How many square deckles would this be if 1 deckle = 75.9 yod
STatiana [176]

Answer:

It would be <u>97.50</u> square deckles.

Step-by-step explanation:

Given:

On the distant plant, Mathology, a sports area covers 7400 yodels².

1 deckle = 75.9 yodels.

Now, to get the square deckles.

As given, 1 deckle = 75.9 yodels.

So, to get the square deckles by using conversion factor:

<em>75.9 yodels = 1 deckle.</em>

7400 yodels² = 7400\div 75.9

                       = 97.50\ deckels ^2.

Therefore, it would be 97.50 square deckles.

8 0
3 years ago
The square root of 52 is between which two consecutive Integers?
Murrr4er [49]
The answer is 7 and 8
7 0
3 years ago
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Find the area of a regular hexagon
xxMikexx [17]
<h2><em>Answer:</em></h2><h2><em>4</em><em>2</em><em> </em><em>cm^</em><em>2</em></h2>

<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>

<em>hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em>

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4 0
3 years ago
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