The numbers are: "7 " and "21 " .
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Explanation:
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The numbers are: "x" and "x + 14" .
x + (x + 14) = 28 . Solve for "x" ; and then solve for "x + 14" .
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→ x + (x + 14) = 28 ;
Rewrite as:
→ x + x + 14 = 28 ;
→ 1x + 1x + 14 = 28 ;
→ 2x + 14 = 28 ;
Subtract "14" from each side of the equation;
→ 2x + 14 − 14 = 28 <span>− 14 ;
</span> → 2x = 14 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 2x / 2 = 14 / 2 ;
→ x = 7 .
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So; one of the numbers is: " 7 " .
The other number is: " x + 14 " ; which equals: " 7 + 14 = 21".
The other number is: "21 " .
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The numbers are: "7 " and "21 " .
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um oki ...... -_- ahhhahahhahahah
Answer:
97+x
Step-by-step explanation:
Let x represent how many cards he got.
3y+14=44
Answer: First step is to subtract 14 from each side
3y = 30 (divide each side by 3)
y = 30/3, y = 10