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Leni [432]
3 years ago
10

Suppose you invested $1500 in an ac count that paid an annual of 3% compound monthly. How much would you have after 1 year

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

1545.62

Step-by-step explanation:

The calculation of compound interests uses this formula:

<h2>A = P (1 + \frac{r}{n} )^{n*t}</h2>

Where  A = total amount, P = principal or amount of money deposited, r = annual interest rate, n = number of times compounded per year  and t = time in years.

So, if we plug-in the numbers of the problem we have:

<h2>A = 1500 (1 + \frac{0.03}{12} )^{12*1}</h2>

Which gives us:

A = 1500 * 1.0025^{12} = 1500 * 1.030416 = 1545.62

For a grand total of 1,545.62 including capital and interests.

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madam [21]

We will see that the probability of x taking on a value between 75 to 90 is P = 0.5

<h3>How to get the probability?</h3>

We know that x is a continuous random variable uniformly distributed between 65 and 85.

This means that the probability that x value y in the range is such that:

1 = P(y)*(85 - 65) = P(y)*20

1/20 = P(y).

Now, the probability of x taking a value between 75 and 85 is:

P(75 to 85) = (1/20)*(85 - 75) = 10/20 = 0.5

And the probability between 85 and 90 is zero (because the maximum value that x can take is 85, so this part does not affect).

Then we conclude that the probability of x taking a value between 75 to 90 is:

P(75 to 90) = P(75 to 85) + P(85 to 90) = 0.5 + 0 = 0.5

If you want to learn more about probability, you can read:

brainly.com/question/251701

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When the rate of change varies from point to point, the relationship is a
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