Answer:
For a point defined bt a radius R, and an angle θ measured from the positive x-axis (like the one in the image)
The transformation to rectangular coordinates is written as:
x = R*cos(θ)
y = R*sin(θ)
Here we are in the unit circle, so we have a radius equal to 1, so R = 1.
Then the exact coordinates of the point are:
(cos(θ), sin(θ))
2) We want to mark a point Q in the unit circle sch that the tangent has a value of 0.
Remember that:
tan(x) = sin(x)/cos(x)
So if sin(x) = 0, then:
tan(x) = sin(x)/cos(x) = 0/cos(x) = 0
So tan(x) is 0 in the points such that the sine function is zero.
These values are:
sin(0°) = 0
sin(180°) = 0
Then the two possible points where the tangent is zero are the ones drawn in the image below.
The answer is x=5. I've included the work in the picture attached.
Answer:

Step-by-step explanation:
You only need to isolate the term a to solve this problem.
Add by 3 from both sides.

Solve.
0+3=3
a/7<3
Multiply by 7 from both sides.

Solve.
3*7=21
<u>a<21</u>
As a result, the solution is a<21, which is our answer.
For
(a-b)(a+b)=a^2-b^2
x^2-y^2-14x+49
x^2-14x+49-y^2
(x-7)^2-y^2
(x-7-y)(x-7+y)
or
(x-y-7)(x+y-7)
Line symmetry this is because if you cut a straight line down the middle it would be the exact same size