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Paha777 [63]
3 years ago
6

***PLEASE HELP I'M TIMED***

Mathematics
2 answers:
Natalija [7]3 years ago
6 0

Answer:

Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively

Step-by-step explanation:

We have the functions, f(x) = eˣ and g(x) = x+6

So, their composition will be g(f(x)).

Then, g(f(x)) = g(eˣ) = eˣ+6

Thus, g(f(x)) = eˣ+6.

Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.

Moreover, the function g(f(x)) = eˣ+6 is the function f(x) translated up by 6 units.

Hence, the domain and range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively.

lilavasa [31]3 years ago
4 0

Answer:

It is not D!!!! it is not all real numbers for both! I got it wrong!

Step-by-step explanation:

edge 2021

i had answered saying it was D but then I got it wrong, so I can't just delete my answer. But I can say it is absolutely not D.

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I will give brainliest answer
dalvyx [7]

Answer:

  4 right; 4 up

Step-by-step explanation:

The difference between the two points is ...

  P'(1, 5) -P(-3, 1) = (1-(-3), 5-1) = (4, 4)

The translation is 4 units to the right and 4 units up.

8 0
3 years ago
Uhm ian askin fo a lot buh ,,, uh someone add me on Rblx , XxColdTyXx is da user
ch4aika [34]

Answer:

Mk! I will when I get my account back!

Step-by-step explanation:

4 0
2 years ago
Question 18
kobusy [5.1K]

Answer:

Undefined

Step-by-step explanation:

y=-7 has a slope of 0, since it is a horizontal line. The only types of lines that are perpendicular to horizontal lines are vertical lines, which are usually in the form x=a (where a is any real number). Vertical lines have an undefined slope, so the answer is undefined. Hope this helps!

6 0
2 years ago
I NEED HELP PLEASE ASAP PLEASE IM BEGGING YOU PLEASE!!!!!!!!!!!
Evgesh-ka [11]
Where’s the picture?
6 0
3 years ago
Read 2 more answers
Subtract (x^2+3x-4) -(4x-2x^2-3)
Feliz [49]

Answer:

3 x^2 - x + -1

Step-by-step explanation:

Simplify the following:

-(4 x - 2 x^2 - 3) + x^2 + 3 x - 4

Factor -1 out of -2 x^2 + 4 x - 3:

--(2 x^2 - 4 x + 3) + x^2 + 3 x - 4

(-1)^2 = 1:

2 x^2 - 4 x + 3 + x^2 + 3 x - 4

Grouping like terms, 2 x^2 + x^2 + 3 x - 4 x - 4 + 3 = (x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3):

(x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3)

x^2 + 2 x^2 = 3 x^2:

3 x^2 + (3 x - 4 x) + (-4 + 3)

3 x - 4 x = -x:

3 x^2 + -x + (-4 + 3)

3 - 4 = -1:

Answer: 3 x^2 - x + -1

4 0
3 years ago
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