Hello DestinyKiara99 o/
We can solve this equation using the quadratic formula
Check it out...
x² + 6x - 24 = 0
Δ = 6² - 4.1.(-24)
Δ = 36 + 96
Δ = 132
x = -6 +/- √132 x' = -3 + √33
<span> -------------- /
2 \
x'' = - 3 - </span>√33
The correct answer is the letter D
I hope this help =)
this is a question from me to you not an answer sorry what class are you taking
Answer:
Step-by-step explanation:
Diameter = 28 cm
therefore, radius = 28 / 2 = 14 cm
Circumference = 2 π r
= 2 × 22 / 7 × 14
= <u><em>88 cm</em></u>
Hope this helps
plz mark as brainliest!!!!!
Answer:
The volume of the tumor experimented a decrease of 54.34 percent.
Step-by-step explanation:
Let suppose that tumor has an spherical geometry, whose volume (
) is calculated by:
Where 
is the radius of the tumor.
The percentage decrease in the volume of the tumor (
) is expressed by:
Where:
- Absolute decrease in the volume of the tumor.
- Initial volume of the tumor.
The absolute decrease in the volume of the tumor is:
The percentage decrease is finally simplified:
![\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V%20%3D%20%5Cleft%5B1-%5Cleft%28%5Cfrac%7BR_%7Bf%7D%7D%7BR_%7Bo%7D%7D%5Cright%29%5E%7B3%7D%20%5Cright%5D%5Ctimes%20100%5C%2C%5C%25)
Given that 
and 
, the percentage decrease in the volume of tumor is:
![\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V%20%3D%20%5Cleft%5B1-%5Cleft%28%5Cfrac%7B0.77%5Ccdot%20R%7D%7BR%7D%5Cright%29%5E%7B3%7D%20%5Cright%5D%5Ctimes%20100%5C%2C%5C%25)
The volume of the tumor experimented a decrease of 54.34 percent.
48 i believe thats the best i can find
