The distribution is not a standard normal distribution.
We know that the variable (X) usually obeys and follows a standard normal distribution provided that the summation of (X) is zero and the variance of the random variable V(X) = 1.
Mathematically:
E(X) = 0 and V(X) = 1
Given that;
- the mean which follows a normal distribution (X) = 4.5338 g, and
- the standard deviation SD(X) = 0.1039 g
As such, the distribution is not a standard normal distribution.
Therefore, we can conclude that the distribution is not a standard normal distribution.
Learn more about standard normal distribution here:
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The method we need to use here is very particular to this type of a situation. The way we will find that polynomial, or the divisor, is to follow this formula:
. For us that will look like this:
. First we will simplify as much as possible that very long numerator there. It simplifies to
. What you do now is use long division of polynomials, which, unfortunately, is impossible to show in this forum. However, get familiar with the long division process if you are not already, and you will find that your polynomial g(x) is
.
H f g g g g g g g g g. G g g g. G g r e e e e e e e e e e e e e e e e
The distributive property:
a(b + c) = ab + ac
2(x - 8) = 68
(2)(x) - (2)(8) = 68
2x - 16 = 68 |+16
2x = 84 |:2
x = 42
Answer: D. 42
Answer:
y=(7)^x represents the exponential growth
