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AlekseyPX
3 years ago
10

WILL MARK BRAINLIEST IF CORRECT AND PLS HURRY IM TIMED

Mathematics
2 answers:
Alex777 [14]3 years ago
5 0

Answer:

The answer is x^2(x+11)-3(x+11)

Step-by-step explanation:

took the quiz :)

Tpy6a [65]3 years ago
4 0

Answer:

x^2 (x + 11) - 3 (x + 11)

Step-by-step explanation:

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3 years ago
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If angle 1 and angle 2 are supplementary angles, and angle 3 and angle 2 are supplementary angles, what do you know about angle
dusya [7]

Answer:

  angle 1 and angle 3 are congruent

Step-by-step explanation:

Angles supplementary to the same angle are congruent. Here both angles 1 and 3 are supplementary to angle 2, so angles 1 and 3 are congruent.

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If you like, you can get there algebraically:

  m∠1 + m∠2 = 180

  m∠3 + m∠2 = 180

Subtract the second equation from the first:

  (m∠1 + m∠2) - (m∠3 + m∠2) = (180) - (180)

  m∠1 -m∠3 = 0 . . . . simplify

  m∠1 = m∠3 . . . . . . add m∠3

When angle measures are the same, the angles are congruent.

  ∠1 ≅ ∠3

4 0
4 years ago
Simplify each equation <br> (x^4)(x^2)
BartSMP [9]
Ok, so remember the exponentioal law that says
( x^{m} )(x^{n})=x^{m+n} so


( x^{4} )(x^{2})=x^{4+2}= x^{6}

answe ris x^6
5 0
3 years ago
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James flipped a quarter 40 times he flipped a head 18 times and a tale 22 times using his data what is the experimental probabil
natta225 [31]
The answer would be 22 out of 40
3 0
4 years ago
Find an equation of the plane tangent to the following surface at the given point.z equals tangent Superscript negative 1 Baseli
Sergeeva-Olga [200]

Let <em>f(x</em>, <em>y</em>, <em>z)</em> = <em>z</em> - arctan(<em>x y</em>). Compute the gradient of <em>f</em> at the point (0, 3, 0):

∇ <em>f(x</em>, <em>y</em>, <em>z)</em> = (-<em>y</em> / (1 + <em>x</em>²<em>y</em>²), -<em>x</em> / (1 + <em>x</em>²<em>y</em>²), 1)

∇ <em>f </em>(0, 3, 0) = (-3, 0, 1)

This vector is orthogonal to the surface <em>z</em> = <em>f(x</em>, <em>y)</em>. Then the equation of the tangent plane is

∇ <em>f </em>(0, 3, 0) • (<em>x</em>, <em>y</em> - 3, <em>z</em>) = 0

(-3, 0, 1) • (<em>x</em>, <em>y</em> - 3, <em>z</em>) = 0

-3<em>x</em> + <em>z</em> = 0

<em>z</em> = 3<em>x</em>

5 0
3 years ago
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