Answer:
2 and 3
Step-by-step explanation:
6 = 2 × 3, so if a number is divisible by 6, it is also divisible by 2 and 3.
Answer:
5
Step-by-step explanation:
Plug n the h and j so you get 6-(2-1). Due to PEMDAS you do the parenthesis first then subtract so it become 6-1=5. ( You could use distributive property)
Answer:
Sarah bought 7 coach tickets and 4 first class tickets.
Step-by-step explanation:
From the information provided, you can write the following equations:
x+y=11 (1)
240x+1100y=6080 (2), where:
x is the number of coach tickets
y is the number of first class tickets
In order to find the value of x and y, first you have to solve for x in (1):
x=11-y (3)
Now, you have to replace (3) in (2) and solve for y:
240(11-y)+1100y=6080
2640-240y+1100y=6080
860y=6080-2640
860y=3440
y=3440/860
y=4
Finally, you can replace the value of y in (3) to find the value of x:
x=11-y
x=11-4
x=7
According to this, the answer is that Sarah bought 7 coach tickets and 4 first class tickets.
15 i am pretty sure i’m probably gonna be wrong
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN