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prisoha [69]
3 years ago
11

Help! this is algebra 1 and idk how to do it lol

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0

Answer:

a. x+6 = 0

b. y-2 = 0

Step-by-step explanation:

Given point is:

(-6,2)

<u>a. Line perpendicular to x-axis:</u>

A line perpendicular to x-axis means that the line is vertical and parallel to y-axis. Any equation parallel to y-axis has the form

x = k

where k is the x-coordinate of the point from which the line passes.

So the required equation is:

x = -6\\x+6 = 0

<u>b. Line perpendicular to y-axis:</u>

A line perpendicular to y-axis will be a horizontal line parallel to x-axis having the equation of the form

y = b

where b is the y-intercept

Required equation is:

y = 2\\y-2=0

Hence,

a. x+6 = 0

b. y-2 = 0

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