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3 years ago

All I need is the answer and if you answer absolutely right you will be marked THE BRAINLIEST

Mathematics

1 answer:

Anettt [7]3 years ago

5 0

Pretty sure it would be E

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PLEASE SOMEONE HELP ME WITH THESE QUESTIONS I'VE BEEN STUCK ON HERE FOR SO LONG

Neporo4naja [7]

Answer:

# means number

Step-by-step explanation:

Distance = Y-axis or output

Cost= X-axis or input

you do not need to add the brackets for the formula(BEDMAS), but it makes things clearer

For A -

the Y-intercept is where the first coordinate, or the # or the X-axis, is 0 (on the graph the y-intercept 0,4)

For B -

y = mx + b

m = slope

x = input or # on the X-axis

b = y-intercept

formula = (input x increase in the slope) + output for 0 or (distance x increase in cost) + output for 0

input(x axis) output(y axis)

0 5 ← output for 0

1 9

2 13

there is a +4 increase in the slope, the increase in the slope is an output #(in this case 9) - the previous output number (in this case 5)

formula = (input x increase in the slope) + output for 0 = distance

formula in use = (3 x 4) + 5 = 17

For C:

The dependent variable is the output or the cost because the input or the distance will determine the cost travelled. Eg. if I travel 9 miles it will cost $41. If the dependent variable is the cost then the independent variable is the distance

For D: (input x increase in the slope) + output for 0

(4.2 miles x $4) + 5

16.8 + 5 = $21.8; It will cost $21.8 to travel 4.2miles

For E: (distance x increase in cost) + output for 0

(? x 4) + 5 = 14

(14 - 5) = 9

9 ÷ 4 = 2.25miles; with 14 dollars I could travel 2.25 miles

(It is a bit confusing lol, but this is the way I understand it, if you can't understand it this way then use y = mx + b)

4 0

2 years ago

The sides of a right triangle containing the right angle are (5x) cm and (3x - 1) cm. If the area of the triangle be 60 cm, calc

ladessa [460]

Answer: hypotenuse (h) = 17 cm

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

if the sum of a number and nine is doubled, the result is seven less than the number. find the number.

avanturin [10]

X=the number we have to find.
This expression "2(x+9)" is when the sum of a number and nine is doubled.
If the result is seven less than the number, we will have: x-7

We can suggest the following equation:
2(x+9)=(x-7)
2x+18=x-7
2x-x=-7-18
x=-25

answer: the number would be: -25.

3 0

2 years ago

Match each vector operation with its resultant vector expressed as a linear combination of the unit vectors i and j.

Cloud [144]

Answer:

3u - 2v + w = 69i + 19j.

8u - 6v = 184i + 60j.

7v - 4w = -128i + 62j.

u - 5w = -9i + 37j.

Step-by-step explanation:

Note that there are multiple ways to denote a vector. For example, vector u can be written either in bold typeface "u" or with an arrow above it $\vec{u}$ . This explanation uses both representations.

$\displaystyle \vec{u} = \langle 11, 12\rangle =\left(\begin{array}{c}11 \\12\end{array}\right)$ .

$\displaystyle \vec{v} = \langle -16, 6\rangle= \left(\begin{array}{c}-16 \\6\end{array}\right)$ .

$\displaystyle \vec{w} = \langle 4, -5\rangle=\left(\begin{array}{c}4 \\-5\end{array}\right)$ .

There are two components in each of the three vectors. For example, in vector u, the first component is 11 and the second is 12. When multiplying a vector with a constant, multiply each component by the constant. For example,

$3\;\vec{v} = 3\;\left(\begin{array}{c}11 \\12\end{array}\right) = \left(\begin{array}{c}3\times 11 \\3 \times 12\end{array}\right) = \left(\begin{array}{c}33 \\36\end{array}\right)$ .

So is the case when the constant is negative:

$-2\;\vec{v} = (-2)\; \left(\begin{array}{c}-16 \\6\end{array}\right) =\left(\begin{array}{c}(-2) \times (-16) \\(-2)\times(-6)\end{array}\right) = \left(\begin{array}{c}32 \\12\end{array}\right)$ .

When adding two vectors, add the corresponding components (this phrase comes from Wolfram Mathworld) of each vector. In other words, add the number on the same row to each other. For example, when adding 3u to (-2)v,

$3\;\vec{u} + (-2)\;\vec{v} = \left(\begin{array}{c}33 \\36\end{array}\right) + \left(\begin{array}{c}32 \\12\end{array}\right) = \left(\begin{array}{c}33 + 32 \\36+12\end{array}\right) = \left(\begin{array}{c}65\\48\end{array}\right)$ .

Apply the two rules for the four vector operations.

$\displaystyle \begin{aligned}3\;\vec{u} - 2\;\vec{v} + \vec{w} &= 3\;\left(\begin{array}{c}11 \\12\end{array}\right) + (-2)\;\left(\begin{array}{c}-16 \\6\end{array}\right) + \left(\begin{array}{c}4 \\-5\end{array}\right)\\&= \left(\begin{array}{c}3\times 11 + (-2)\times (-16) + 4\\ 3\times 12 + (-2)\times 6 + (-5) \end{array}\right)\\&=\left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle\end{aligned}$

Rewrite this vector as a linear combination of two unit vectors. The first component 69 will be the coefficient in front of the first unit vector, i. The second component 19 will be the coefficient in front of the second unit vector, j.

$\displaystyle \left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle = 69\;\vec{i} + 19\;\vec{j}$ .

$\displaystyle \begin{aligned}8\;\vec{u} - 6\;\vec{v} &= 8\;\left(\begin{array}{c}11\\12\end{array}\right) + (-6) \;\left(\begin{array}{c}-16\\6\end{array}\right)\\&=\left(\begin{array}{c}88+96\\96 - 36\end{array}\right)\\&= \left(\begin{array}{c}184\\60\end{array}\right)= \langle 184, 60\rangle\\&=184\;\vec{i} + 60\;\vec{j} \end{aligned}$ .

$\displaystyle \begin{aligned}7\;\vec{v} - 4\;\vec{w} &= 7\;\left(\begin{array}{c}-16\\6\end{array}\right) + (-4) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}-112 - 16\\42+20\end{array}\right)\\&= \left(\begin{array}{c}-128\\62\end{array}\right)= \langle -128, 62\rangle\\&=-128\;\vec{i} + 62\;\vec{j} \end{aligned}$ .

$\displaystyle \begin{aligned}\;\vec{u} - 5\;\vec{w} &= \left(\begin{array}{c}11\\12\end{array}\right) + (-5) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}11-20\\12+25\end{array}\right)\\&= \left(\begin{array}{c}-9\\37\end{array}\right)= \langle -9, 37\rangle\\&=-9\;\vec{i} + 37\;\vec{j} \end{aligned}$ .

7 0

3 years ago

What is the total surface area of rectangular prism?

algol13

Answer:

162 [m²].

Step-by-step explanation:

required surface is:

A=(3*7+6*7+3*6)*2=162 [m²].

4 0

2 years ago

Read 2 more answers