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Natali [406]
3 years ago
5

Advanced Mathematical Decision Making..... The height is ____ the distance is_____

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0
The height is 40 and the distance is 70
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How do you do this? please help me
Anastaziya [24]

Answer:

f = 10, g = 4.8 cm

Step-by-step explanation:

Area of ABCE = 60 cm²

Area of ABCD = 48 cm²

So,

Area of ADE = 60-48

=> 12 cm²

Area of ADE = \frac{1}{2} (Base)(Height)

<u><em>Where Area = 12 cm², Base = 4 cm</em></u>

12 = \frac{1}{2}(4)(Height)

Height = 12-2

Height = 10 cm

Where Height is AD

So, AD = 10 cm

Also, <u><em>AD is parallel and equal to BC</em></u>(f)<u><em></em></u>

So,

f = 10 cm

<u><em>Now, Finding g</em></u>

Area of ABCD = Base * Height

<u><em>Where Area = 48 cm², Base = 10 cm</em></u>

48 = 10 * Height

Height = 48/10

Height = 4.8 cm

Whereas, Height is g

So, g = 4.8 cm

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