How do you do cube roots? ∛8????

Mathematics

1 answer:

nikitadnepr [17]3 years ago

5 0

Answer:

8 = 2×2×2

$\sqrt[3]{8}$ = ∛2x2x2

=∛(2)(2)(2)

=∛2³

hence ∛8 = 2

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Step-by-step explanation:

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3 years ago

A quadratic equation is shown below: x2 − 8x + 13 = 0 Which of the following is the first correct step to write the above equati

Andreyy89

Answer:

<u>Add 3 to both sides of the equation</u>

Solution:

The first step is to basically realize that all it's asking you to do is to find a way to make the expression on the left ( $x^2 - 8x + 13$ ) into an expression that is a perfect square. So what number should you add to both sides such that $x^2 - 8x + (13 + j)$ can be factored into $(x-p)^2$ ? Well, we can approach it like this:

Since $(x-p)^2$ can be turned into $x^2 -2px + p^2$ , and our original form was $x^2 - 8x + (13 + j)$ , we quickly realize that $-2px = -8x$ . From there, we can easily tell that $p = 4$

Plug this into our last value $p^2$ to get 16. Therefore, if we compare this with our original equation again $x^2 - 8x + (13 + j)$ , we notice that 13 + j = 16.

Thus, j = 3 for the last answer.

Add 3 to both sides of the equation.

Note: With more practice, you will quickly gain enough intuition to notice that $x^2 - 8x + 13$ is very close to $x^2 - 8x + 16$ which can be factored into $(x-4)^2$ . But for now, the solution above will suffice. I hope this helps :))