The answer to this question is 3.15
maybe XD
<h3>
Answer: C) incenter</h3>
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Explanation:
If you were to intersect the angle bisectors (at least two of them), then you would locate the incenter. The incenter is the center of the incircle which is a circle where it is as large as possible, but does not spill over and outside the triangle. Therefore this circle fits snugly inside the triangle.
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extra notes:
* The centroid is found by intersecting at least two median lines
* The circumcenter is found by intersecting at least two perpendicular bisector lines
* The orthocenter is found by intersecting at least two altitude lines
* The incenter is always inside the triangle; hence the "in" as part of the name. The centroid shares this property as well because the medians are completely contained within any triangle. The other two centers aren't always guaranteed to be inside the triangle.
* The red lines cut each angle of the triangle into two equal or congruent pieces.
Answer:George
Step-by-step explanation: George is correct because Emma said that the total number of pools in the city is 11 even though it says there are 16 pools in the city, but she got the number of how many are open, George is right because it says what is the ratio of pools open on the weekends to the total amount of pools, and it says there are 6 pools open on the weekend and there are 16 pools in the city in total so he would do 6:16.
Answer:
The first three terms are -30, -27 and -24
Step-by-step explanation:
The formula for nth term of a arithmetic series is given by:
aₙ = a₁ + (n - 1)d
Substitute n = 16 in the given equation:
a₁₆ = a₁ + (16 - 1)d
Where aₙ = a₁₆ = 15. Substitute in the given equation
15 = a₁ + 15d ⇒ Equation (i)
Sum of arithmetic sequence is given by:
Sₙ = n(a₁ + aₙ) / 2
Substitute n = 16 in the above equation:
S₁₆ = 16(a₁ + a₁₆) / 2
Where S₁₆= -120 and a₁₆=15, substitute:
-120 = 16(a₁ + 15)/2
-240 = 16(a₁ +15)
-15 = a₁ + 15
a₁ = -30
Substitute it in Equation (i)
15 = a₁ + 15d
15 = -30 + 15d
15d = 15+30
d = 45/15
d = 3
So
a₁ = -30
a₂ = a₁ + (2-1)d
a₂ = -30 + 3
a₂ = -27
a₃ = a₁ + (3-1)d
a₃ = a₁ + 2d
a₃ = -30 + 2(3)
a₃ = -30 +6
a₃ = -24
