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Nimfa-mama [501]
3 years ago
12

Help with this math question please

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0
Re-arranging the inequality to find the test points:

x- \frac{70}{x}\ \textless \ -3 \\  \\ 
 x- \frac{70}{x}+3\ \textless \ 0 \\  \\ 
 \frac{ x^{2} -70+3x}{x}\ \textless \ 0 \\  \\ 
 \frac{(x-7)(x+10)}{x}\ \textless \ 0

This means, we need to test the inequality for x = -10, x = 0 and x = 7

Since question assumes that x > 0, so we ignore the values less than 0.
So the test points are x = 0 and x = 7

At x = 0 the expression is undefined.
Between x = 0 and x = 7 the value of expression \frac{(x-7)(x+10)}{x} is negative. At x = 7 the value of expression is 0. Above x = 7 the value of expression is positive. 

So, the solution to the given inequality will be 0 < x < 7.
In Interval notation, the solution can be written as (0,7)
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Which box-and-whisker plot represents the data set?<br><br> 11, 6, 19, 14, 21, 7, 13, 15, 15
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vladimir2022 [97]

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Read 2 more answers
the vertices of PQR are P(-5,1), Q(-4,6), and R(-2,3), graph P"Q"R" after a composition of the transformations in the order they
horsena [70]

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In R(-2,3), x = -2 and y = 3

\begin{gathered} P(-5,\text{ 1) translates to (-5 -8, 1) }\rightarrow P^i(-13,\text{ 1)} \\ Q(-4,\text{ 6) translates to (-4 -8, 6) }\rightarrow Q^i(-12,\text{ 6)} \\ R(-2,\text{ 3) translates to (-2 -8, 3) }\rightarrow R^i(-10,\text{ 3)} \end{gathered}

For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.

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5 0
1 year ago
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