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olya-2409 [2.1K]
3 years ago
8

Using f(x)=2x^2 and g(x)=3x+4. whats (g of f)(5)? whats (f of g)(5)?​

Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

f(g(x)) = 722, and g(f(x)) = 154

Step-by-step explanation:

f(x) = 2x²

g(x) = 3x + 4

g(f(x)) = 3(2x²) + 4

g(f(5)) = 3(2 × 5²) + 4

g(f(5)) = 3(2 × 25) + 4

g(f(5)) = 3 × 50 + 4

g(f(5)) = 154

f(g(x)) = 2(3x + 4)²

f(g(5)) = 2(3 × 5 + 4)²

f(g(5)) = 2 × 19²

f(g(5)) = 2 × 361

f(g(5)) = 722

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Construct a 96% confidence interval if a sampling distribution has a mean of 20, a standard deviation of 5, and a size of 100.
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Using the t-distribution, the 96% confidence interval is given as follows:

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<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

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In which:

  • \overline{x} is the sample mean.
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  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 96% confidence interval, with 100 - 1 = 99 df, is t = 2.0812.

The parameters are given as follows:

\overline{x} = 20, s = 5, n = 100

Hence the bounds of the interval are:

\overline{x} - t\frac{s}{\sqrt{n}} = 20 - 2.0812\frac{5}{\sqrt{100}} = 18.96

\overline{x} + t\frac{s}{\sqrt{n}} = 20 + 2.0812\frac{5}{\sqrt{100}} = 21.04

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A school authority claims that the average height of students is 178 cm. A researcher has taken a well-designed survey and his s
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Answer:

d) The difference exists due to chance since the test statistic is small

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From the given information:

Population mean = 178 cm

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the standard deviation = 2

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The null hypothesis and the alternative hypothesis can be computed as:

Null hypothesis:

H_o: \mu = 178

Alternative hypothesis:

H_1: \mu \neq 178

The t-test statistics is determined by using the formula:

t = \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}}

t = \dfrac{177.5 - 178}{\dfrac{2}{\sqrt{25}}}

t = \dfrac{-0.5}{\dfrac{2}{5}}}

\mathbf{t= -1.25}

Degree of freedom df = n- 1

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