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3 years ago

14

The four folded parts of an envelope are opened up to create this figure. What is the surface area of one side of the unfolded e

nvelope?
A. 25 square centimeters
B. 37 square centimeters
C. 50 square centimeters
D. 64 square centimeters

2 answers:

Artemon [7]3 years ago

8 0

Answer:

C

Step-by-step explanation:

The total area comprises of the rectangle (area is base * height) and the 4 triangles (area = 1/2 * base * height).

Area of rectangle = 6 * 4 = 24

Area of top triangle = 1/2 * 6 * 3 = 9

Area of bottom triangle = 1/2 * 6 * 3 = 9

Area of rightside triangle = 1/2 * 4 * 2 = 4

Area of leftside triangle = 1/2 * 4 * 2 = 4

Let's add them up and find the correct answer:

Area = 24 + 9 + 9 + 4 + 4 = 50

vichka [17]3 years ago

4 0

Answer:

Option C. 50 square centimeters

Step-by-step explanation:

we know that

The surface area is equal to the area of four triangles plus the area of rectangle

so

$SA=2[\frac{1}{2}(4)(2)]+2[\frac{1}{2}(6)(3)]+(6)(4)$

$SA=8+18+24$

$SA=50\ cm^{2}$

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HI I NEED HELP ASAP I GIVE BRAINLEST IF YOU GET IT RIGHT

lord [1]

It’s c :) I did the test just trust me

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3 years ago

Kate wants to buy a TV that has a price of $450. Kate decides to start saving after

shutvik [7]

Answer:

450 = (15·x) -50

Step-by-step explanation:

You know that the TV cost $450

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you know she saves $15/month

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3 years ago

israel started to solve a radical equation in this way: square root of x plus 6 − 4 = x square root of x plus 6 − 4 4 = x 4 squa

agasfer [191]

Lets solve our radical equation $\sqrt{x+6}-4=x$ step by step.

Step 1 add 4 to both sides of the equation:

$\sqrt{x+6} -4+4=x +4$

$\sqrt{x} +6=x+4$

Step 2 square both sides of the equation:

$\sqrt{x+6} =x+4$

$\sqrt{x+6}^2 =(x+4)^2$

$x+6=(x+4)^2$

Step 3 expand the binomial in the right hand side:

$x+6=x^2+8x+16$

Step 4 simplify the expression:

$0=x^2+8x-x+16-6$

$x^2+7x+10=0$

Step 5 factor the expression:

$(x+2)(x+5)=0$

Step 6 solve for each factor:

$x+2=0$ or $x+5=0$

$x=-2$ or $x=-5$

Now we are going to check both solutions in the original equation to prove if they are valid:

For $x=-2$

$\sqrt{x+6}-4=x$

$\sqrt{-2+6}-4=-2$

$\sqrt{4}-4=-2$

$2-4=-2$

$-2=-2$

The solution $x=2$ is a valid solution of the rational equation $\sqrt{x+6}-4=x$ .

For $x=-5$

$\sqrt{x+6}-4=x$

$\sqrt{-5+6}-4=-5$

$\sqrt{1}-4=-5$

$1-4=-5$

$-3\neq -5$

Since -3 is not equal to -5, the solution $x=-5$ is not a valid solution of the rational equation $\sqrt{x+6}-4=x$ ; therefore, $x=-5$ is an extraneous solution of the equation.

We can conclude that even all the algebraic procedures of Israel are correct, he did not check for extraneous solutions.

An extraneous solution of an equation is the solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation. Is worth pointing out that extraneous solutions are particularly frequent in rational equation.

8 0

3 years ago

To what decimal place should each answer be rounded? How many significant figures does the rounded answer have? A. 9 cm+2.8 cm=1

FromTheMoon [43]

Answer:

a) rounded to the ones place and 2 significant figures.

b) rounded to tenths place and 1 significant figure.

Step-by-step explanation:

Significant figures are the number of needed place values for accuracy. Round each number according to the least number of significant figures within the problem.

A. 9 cm+2.8 cm = 11.8 cm rounds to 12 which has 2 significant figures. Round to the ones place value since 9 has the least number of significant figures.

B. 0.135 atm+0.6 atm = 0.735 atm rounds to 0.7 atm which has 1 significant figure. Zero preceding the value is not considered significant. Round to the tenths place value since 0.6 has the least number of significant figures.

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3 years ago

Describe two ways to tell if a graph is a function

Dima020 [189]

Answer:

Inspect the graph to see if any vertical line drawn would intersect the curve more than once. If there is any such line, the graph does not represent a function. If no vertical line can intersect the curve more than once, the graph does represent a function.

Step-by-step explanation:

Hope that helps you out!

I wouldnt mind if you marked brainliest hehehe

Have a good day!

8 0

3 years ago