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ss7ja [257]
3 years ago
8

Question is: Andre solved an equation, but when he checked his answer he saw his solution was incorrect. He knows he made a mist

ake, but can’t find it. Where is andres mistake and what is the solution to the equation?

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

-1=x He messed up on the third step.

Step-by-step explanation:

I worked out the equation and found that when he switched -6x over to -4 he did not change the symbol. So instead of 6+4 he did 4-6. I finished the equation and got -1

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What is the volume cubic inches of a box when the length is 8 inches, the width is 3 inches and the height is 10 inches?
erica [24]

Answer:

240 inches cubed

Step-by-step explanation:

Volume = L x W x H

Take 8 x 10x 3 = 240

dont forget to put inches cubed (in.^3)

4 0
4 years ago
Read 2 more answers
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
aliya0001 [1]

Answer:

A=1500-1450e^{-\dfrac{t}{250}}

Step-by-step explanation:

The large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved.

Volume = 500 gallons

Initial Amount of Salt, A(0)=50 pounds

Brine solution with concentration of 2 lb/gal is pumped into the tank at a rate of 3 gal/min

R_{in} =(concentration of salt in inflow)(input rate of brine)

=(2\frac{lbs}{gal})( 3\frac{gal}{min})\\R_{in}=6\frac{lbs}{min}

When the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

Concentration c(t) of the salt in the tank at time t

Concentration, C(t)=\dfrac{Amount}{Volume}=\dfrac{A(t)}{500}

R_{out}=(concentration of salt in outflow)(output rate of brine)

=(\frac{A(t)}{500})( 2\frac{gal}{min})\\R_{out}=\dfrac{A}{250}

Now, the rate of change of the amount of salt in the tank

\dfrac{dA}{dt}=R_{in}-R_{out}

\dfrac{dA}{dt}=6-\dfrac{A}{250}

We solve the resulting differential equation by separation of variables.  

\dfrac{dA}{dt}+\dfrac{A}{250}=6\\$The integrating factor: e^{\int \frac{1}{250}dt} =e^{\frac{t}{250}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{250}}+\dfrac{A}{250}e^{\frac{t}{250}}=6e^{\frac{t}{250}}\\(Ae^{\frac{t}{250}})'=6e^{\frac{t}{250}}

Taking the integral of both sides

\int(Ae^{\frac{t}{250}})'=\int 6e^{\frac{t}{250}} dt\\Ae^{\frac{t}{250}}=6*250e^{\frac{t}{250}}+C, $(C a constant of integration)\\Ae^{\frac{t}{250}}=1500e^{\frac{t}{250}}+C\\$Divide all through by e^{\frac{t}{250}}\\A(t)=1500+Ce^{-\frac{t}{250}}

Recall that when t=0, A(t)=50 (our initial condition)

50=1500+Ce^{-\frac{0}{250}}50=1500+Ce^{0}\\C=-1450\\$Therefore the amount of salt in the tank at any time t is:\\A=1500-1450e^{-\dfrac{t}{250}}

4 0
4 years ago
Pls do it for me it
anzhelika [568]

Answer:

t=75 3x=75 and y=30

Step-by-step explanation:

t and 3x are equivalent because the sides are the same lengths. knowing that you can subtract 105 from 180 getting 75 for t, knowing that t and 3x are equivalent you also get the answer for 3x witch is 75. the sum of all the angles is 180 and adding 3x and t you get 150, subtracting 150 from 180 you get 30 the answer to degree y.  

4 0
3 years ago
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Susan has 2 five-dollar bills and 3 ten-dollar bills in her purse and 11 one-dollar bills in her pocket. How much money does she
trasher [3.6K]

Answer:

51

Step-by-step explanation:

2*5=10

3*10=30

11*1=11

10+30+11

51

7 0
3 years ago
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SVETLANKA909090 [29]

Answer:

7

Step-by-step explanation:

as it does that F thing where its equal to it....

8 0
3 years ago
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