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3 years ago

What is 0.¯42 expressed as a fraction in simplest form?

Mathematics

2 answers:

Anastaziya [24]3 years ago

4 0

Answer:

Part B (solution): For 0.42... (with the two repeating forever), we need to break up the decimal into the part that does not repeat and the part that repeats.

For the part that does not repeat, pretend that the repeating part is not there (so you have 0.4). Then think about place value. The non-repeating part of this decimal (0.4) is 4 tenths, so write that as a fraction: 4/10.

For the part that repeats, pretend the part that does not repeat is not there (so you have 0.2....). Use the rule of 9s, which tells you to put the repeating part (2) over a nine for every place value that is repeating. In this case there is only one repeating place value (again, 2), so we have 2/9. However, since we skipped a place value (the 4 in our given problem), we need to multiply that place value (in this case 1/10) by 2/9, which is 2/90. Finally, we need to add that to 4/10. Make sure your answer is simplified. Click HERE for help on Question 1.

Part C (solution): For 0.42... (with the four AND two repeating forever), use the rule of 9s. The rule of 9s tells you to put the repeating part (42) over a nine for every place value that is repeating. In this case there is two repeating place values, so we have 42/99. Make sure your answer is simplified. Click HERE for help on Question 1.

Parts A-C (work shown): Please make sure you include all of your work. Click HERE for help on Question 1.

Question 2

Part A (explanation): Please explain what this student did wrong. What was his error? It might be helpful to estimate √75 the way you know how. That should help you see what this student did wrong. Click HERE for help on Question 2.

Part B (solution): Estimate the value of √75 to the nearest tenth. 75 is between the perfect squares 64 and 81. So √75 is between 8 and 9. The distance from 64 to 75 is 11. The distance from 64 to 81 is 17. The ratio is 11/17, or about .647. So, √75 is about .647 bigger than 8. Click HERE for help on Question 2.

Question 3

Part A - (work for π): Approximate the value of π to the nearest tenth. Click HERE for help on Question 3.

Part A - (work for √3): Approximate the value of √3 to the nearest tenth. 3 is between the perfect squares 1 and 4. So √3 is between 1 and 2. The distance from 1 to 3 is 2. The distance from 1 to 4 is 3. The ratio is 2/3, or about .7. So, √3 is about .7 bigger than 1. Click HERE for help on Question 3.

Part A - (work for √5): Approximate the value of √5 to the nearest tenth. 5 is between the perfect squares 4 and 9. So √5 is between 2 and 3. The distance from 4 to 5 is 1. The distance from 4 to 9 is 5. The ratio is 1/5, or .2. So, √5 is about .2 bigger than 2. Click HERE for help on Question 3.

Part A - (work for 2√5): Approximate the value of 2√5 to the nearest tenth. 5 is between the perfect squares 4 and 9. So √5 is between 2 and 3. The distance from 4 to 5 is 1. The distance from 4 to 9 is 5. The ratio is 1/5, or .2. So, √5 is about .2 bigger than 2. Now multiply that value by 2. Click HERE for help on Question 3.

Y_Kistochka [10]3 years ago

3 0

Answer:

21/50

Step-by-step explanation:

0.42 = 42/100, or 21/50 (in simplest form).

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Allowance method entries

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Using the Allowance Method, the relevant transactions can be completed in the books of Wild Trout Gallery as follows:

1. Allowance for Doubtful Accounts

Accounts Debit Credit

Jan. 1 Beginning balance $53,800

Jan. 19 Accounts Receivable 2,560

Apr. 3 Accounts Receivable $14,670

July 16 Accounts Receivable 19,725

Nov. 23 Accounts Receivable 4,175

Dec. 31 Accounts Receivable 25,110

Dec. 31 Ending balance $56,500

Dec. 31 Bad Debts Expenses $55,470

Totals $116,005 $116,005

Accounts Receivable

Accounts Debit Credit

Jan. 1 Beginning balance $2,290,000

Jan. 19 Allowance for Doubtful 2,560

Jan. 19 Cash $2,560

Apr. 3 Allowance for Doubtful 14,670

July 16 Allowance for Doubtful 19,725

July 16 Cash 6,575

Nov. 23 Allowance for Doubtful 4,175

Nov. 23 Cash 4,175

Dec. 31 Allowance for Doubtful 25,110

Dec. 31 Sales Revenue 8,020,000

Dec. 31 Cash $8,944,420

Dec. 31 Ending balance $1,299,500

Totals $10,316,735 $10,316,735

3. Expected net realizable value of the accounts receivable as of December 31 = $1,243,000 ($1,299,500 - $56,500)

Allowance for Doubtful Accounts ending balance = $40,100 ($8,020,000 x 0.5%)

Allowance for Doubtful Accounts

Accounts Debit Credit

Jan. 1 Beginning balance $53,800

Jan. 19 Accounts Receivable 2,560

Apr. 3 Accounts Receivable $14,670

July 16 Accounts Receivable 19,725

Nov. 23 Accounts Receivable 4,175

Dec. 31 Accounts Receivable 25,110

Dec. 31 Ending balance $40,100

Dec. 31 Bad Debts Expenses $39,070

Totals $99,605 $99,605

4. a. Bad Debt Expense for the year = $39,070

4.b. Balance for Allowance Accounts = $40,100

4.c. Expected net realizable value of the accounts receivable = $1,259,400 ($1,299,500 - $40,100)

Data Analysis:

Jan. 19 Accounts Receivable $2,560 Allowance for Uncollectible Accounts $2,560

Jan. 19 Cash $2,560 Accounts Receivable $2,560

Apr. 3 Allowance for Uncollectible Accounts $14,670 Accounts Receivable $14,670

July 16 Cash $6,575 Allowance for Uncollectible Accounts $19,725 Accounts Receivable $26,300

Nov. 23 Accounts Receivable $4,175 Allowance for Uncollectible Accounts $4,175

Nov. 23 Cash $4,175 Accounts Receivable $4,175

Dec. 31 Allowance for Uncollectible Accounts $25,110 Accounts Receivable $25,110

Accounts Receivable ending balance = $1,299,500

Allowance for Uncollectible Accounts ending balance = $56,500

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