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lesya692 [45]
2 years ago
5

Hanif says that 2 ( 4s) + 4(3r) is also equivalent to the perimeter of the figure. Is Hanif correct? Justify your answer by subs

tituting values for r and s.​
Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
4 0

Answer:

sviyrabiyrvskursckurvsosourvovurorvuosurkursbkurabiuabrkaubrksubrskburkusbriburskurvs

Step-by-step explanation:

oectivyrwiwvryicurwvurksiayrbisyrbbisyrcursvirysbaiyejayebiusvrisvryiabeyajyenbiysekayebjvyeaajyebaejbyajybjseybjebyjbeyjaeybjayebjayeb

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Please help!!!!!!!!!!!!!!!!!
nadya68 [22]

Answer: 5 up 10 over

Step-by-step explanation:

I had this on my quiz

3 0
2 years ago
What is the slope of a line that is perpendicular to the graph of y=-3x?
lutik1710 [3]
<span>y=-3x has slope = -3
</span><span>
perpendicular lines, slope is opposite and reciprocal
so slope of </span>perpendicular  = 1/3

answer
1/3
5 0
3 years ago
Are the graphs of the lines in the pair parallel? Explain. y = 4x – 4 24x – 4y = 96
zaharov [31]
No, since the slopes are different

for 1 line
y = 4x - 4

slope = 4

for 2 line
4y = 24x - 96
slope = 24/4 = 6
6 0
3 years ago
Read 2 more answers
Solve by factoring m^2+8m+7=0
Alenkinab [10]
We can use completing the square.We add 16 and subtract 7 to both sides. Now we get m^2+8m+16=9. The left sides becomes (m+4)^2=9. Taking the square root of both sides and subtracting 4 we get -1 and -7.
3 0
2 years ago
Read 2 more answers
Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a
LekaFEV [45]
To make this a little clearer, let's give the pairs of inequalities the same denominator:

<span>Question 1: 
</span>\frac{11}{15} ? \frac{5}{7}
First, apply the common denominator to the first fraction:
(\frac{11}{15})7 \\  \frac{11}{15} *  \frac{7}{7}  \\  \frac{11*7}{15*7}  \\  \frac{77}{105}
Do the same for the second:15( \frac{5}{7}) \\  \frac{5}{7}* \frac{15}{15} \\  \frac{5*15}{7*15}  \\  \frac{75}{105}
Nest, compare the two fractions:
\frac{77}{105} \ \textgreater \   \frac{75}{105}
Therefore:
\frac{11}{15} > \frac{5}{7}
<span>
Question Two:</span>
\frac{5}{9} ? \frac{7}{13}
Apply the common denominator to fraction one:
13( \frac{5}{9}) \\  \frac{5}{9} * \frac{13}{13}  \\  \frac{5*13}{9*13}  \\  \frac{65}{117}
Fraction two:
9(\frac{7}{13}) \\  \frac{7}{13} *  \frac{9}{9}  \\  \frac{7*9}{13*9}  \\  \frac{63}{117}
Evaluate:
\frac{65}{117} > \frac{63}{117}
Therefore:
<span>\frac{5}{9} > \frac{7}{13}
</span>
Hope this helps!
5 0
3 years ago
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