X=5/9g2 but it’s a small 2 ok like g and then the 2 on top lol
Answer:
∠ JKL = 32°
Step-by-step explanation:
Since KN bisects ∠ LKM , then
∠ LKN = ∠ NKM = 35°
Thus
∠ JKL = ∠ JKM - ∠ LKN - ∠ NKM
= 102° - 35° - 35°
= 102° - 70°
= 32°
I assume we are solving for x see attachment.
Answer:
A = 82.53 in²
Step-by-step explanation:
We use the circumference equation C = 2πr and the area equation A = πr².
Using the first equation and the given circumference (32 in), we find the radius of the circle, and then use this result to find the area of the circle.
C 32 in
C = 2πr becomes r = ----------- and here r = ---------- = 5.10 in
2π 6.28
Then the area of the circle is A = πr², which here is A = 3.14(5.10 in)², which, when rounded off to two decimal places, is A = 82.53 in²
Answer:
The answer is the 1st one
Step-by-step explanation:
I risked my answer lucky for you i got it right :)
