Square , rectangle , rombus , parallelogram
Answer:
The graph in the attached figure
Step-by-step explanation:
we know that
In a reflection across the y-axis the y-coordinate remains the same, but the x-coordinate is transformed into its opposite
we have
The reflection of f(x) across the y-axis is equal to the function g(x)
The graph in the attached figure
3x + 20 = 40 + 40
3x = 60
X = 20
V + 71 = 107
V = 36
Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.
Let's see if there are anything we missed:
∞
Σ 2^n=1+2+4+8+16+...
n=0
We multiply (2-1) on both sides:
∞
(2-1) Σ 2^n=(2-1)1+2+4+8+16+...
n=0
And we expand;
∞
Σ 2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)
n=0
But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:
∞
Σ 2^n=-1+2(2^n)
n=0
If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.
Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.
Yep, this shows how weird the infinity sign is.
Answer:
the domain of the function is all real numbers less than or equal to 0
