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ipn [44]
4 years ago
10

How many solutions does this equation have? –8 + t = –t + 10

Mathematics
2 answers:
AleksandrR [38]4 years ago
8 0

Answer:

One solution

Step-by-step explanation:

<em><u>To find the amount of solutions, you must solve first:</u></em>

-8 + t = -t + 10

<em><u>First, add t to both sides:</u></em>

-8 + 2t = 10

<em><u>Add 8 to both sides:</u></em>

2t = 18

<em><u>Divide both sides by 2:</u></em>

t = 9

<u>Since there has been a solution to this equation, that means there's only one solution.</u>

Yuliya22 [10]4 years ago
3 0

Answer:

One

Step-by-step explanation:

Since (1) is the highest exponent value, there can only be one solution.

IF t^2 then there would be two answers.

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A delivery truck made 8 stops in one neighborhood. By stop 5, there were 11 packages delivered.
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3 years ago
I need help with b and d
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Step-by-step:
add (-9) & (+10) to get (+1) : (-9+10 = 1)
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combine (-4x) & (-x) to get (-5x) : (-4x+ (-x) = -4x-x = -5x)
= -5x + y2 + 1 + 3x - 4y2
combine (-5x) & (3x) to get (-2x) : (-5x + 3x = -2x)
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---

D) -4xy + 4y2 - y - 10 or -10 - 4xy - 4y2 (rearrange)
Step-by-step:
subtract 20 from 0 to get −20 (0-20 = -20)
= −20 − 5xy + 4y2 + 10 − y + xy
add (-20) & (10) to get (-10) : (-20+10 = -10)
= -10 -5xy + 4y2 - y + xy
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5 0
4 years ago
The rabbit population in an isolated forest rises and falls depending on the population of predators. Within the year 2014201420
WITCHER [35]

Answer:

Step-by-step explanation:

If within the year 2014, the population p of the rabbits m months after January 2014 is modeled by the equation p = 0.05(m-1.5)(m-8.5) and the population reach 10,000 some time in February, to determine the time, given as months after January 1 2014, that the rabbit population reach ten thousand, we will substitute p = 10 into the modeled equation and get the value of m as shown;

p = 0.05(m-1.5)(m-8.5)+10 \\substitute \ p = 10\\\\ 10 = 0.05(m-1.5)(m-8.5)+10\\\\10-10 =  0.05(m-1.5)(m-8.5)\\\\0 =  0.05(m-1.5)(m-8.5)\\\\0/0.05 =  (m-1.5)(m-8.5)\\\\0 =  (m-1.5)(m-8.5)\\ (m-1.5)(m-8.5) = 0\\ m-1.5 = 0 \ and \ m-8.5 = 0\\m = 1.5 \ and \ 8.5\\

Hence the population of the rabbit reach 10,000 after 1.5 months and 8.5 months

5 0
3 years ago
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