It needs to be 1,2,3,4,5,6,15,39,35
<h3>
Answer: A. 18*sqrt(3)</h3>
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Explanation:
We'll need the tangent rule
tan(angle) = opposite/adjacent
tan(R) = TH/HR
tan(30) = TH/54
sqrt(3)/3 = TH/54 ... use the unit circle
54*sqrt(3)/3 = TH .... multiply both sides by 54
(54/3)*sqrt(3) = TH
18*sqrt(3) = TH
TH = 18*sqrt(3) which points to <u>choice A</u> as the final answer
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An alternative method:
Triangle THR is a 30-60-90 triangle.
Let x be the measure of side TH. This side is opposite the smallest angle R = 30, so we consider this the short leg.
The hypotenuse is twice as long as x, so TR = 2x. This only applies to 30-60-90 triangles.
Now use the pythagorean theorem
a^2 + b^2 = c^2
(TH)^2 + (HR)^2 = (TR)^2
(x)^2 + (54)^2 = (2x)^2
x^2 + 2916 = 4x^2
2916 = 4x^2 - x^2
3x^2 = 2916
x^2 = 2916/3
x^2 = 972
x = sqrt(972)
x = sqrt(324*3)
x = sqrt(324)*sqrt(3)
x = 18*sqrt(3) which is the length of TH.
A slightly similar idea is to use the fact that if y is the long leg and x is the short leg, then y = x*sqrt(3). Plug in y = 54 and isolate x and you should get x = 18*sqrt(3). Again, this trick only works for 30-60-90 triangles.
Answer:
f(x) = -8/3(x+3)+8
a = -8/3
b = technically equals -3 but when we plug it in it gets turned into 3 *double negative
k = 8
Step-by-step explanation:
Vertex: (h,k)
Use the points (0,0) and (-3,8) to find the slope
y2-y1/x2- x1
If you would like to know the number of minutes of long-distance calls you made, you can calculate this using the following steps:
3.3 cents = $0.033
m = $3.40 / 3.3 cents
m = $3.40 / $0.033 = 3.40 / 0.033
m = 103.03 minutes
The correct result would be <span>103.03 minutes.</span>
