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zalisa [80]
3 years ago
9

You had a goal to collect 150 cans for a food drive. You were able to collect 90 cans. What percent of your goal did you collect

?
Mathematics
2 answers:
olga nikolaevna [1]3 years ago
6 0

Answer:

60%

Step-by-step explanation:

hope this helps <3

german3 years ago
5 0

Answer:

60 %

Step-by-step explanation:

multiply .90 * 150

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When x = 5, y = 7000 * 5 + 125000 = $160,000.

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3 years ago
In a large section of a statistics​ class, the points for the final exam are normally​ distributed, with a mean of 71 and a stan
kumpel [21]

Answer:

The lowest score on the final exam that would qualify a student for an​ A is 80.

The lowest score on the final exam that would qualify a student for a B is 74.68.

The lowest score on the final exam that would qualify a student for a C is 67.33.

The lowest score on the final exam that would qualify a student for a​ D is 62.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 71 and a standard deviation of 7.

This means that \mu = 71, \sigma = 7

Grades are assigned such that the top​ 10% receive​ A's, the next​ 20% received​ B's, the middle​ 40% receive​ C's, the next​ 20% receive​ D's, and the bottom​ 10% receive​ F's.

This means that:

90th percentile and above: A

70th percentile and below 90th: B

30th percentile to the 70th percentile: C

10th percentile to the 30th: D

Lowest score for an A:

Top 10% receive A, which means that the lowest score that would qualify a student for an A is the 100 - 10 = 90th percentile, which is X when Z has a pvalue of 0.9, so X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 71}{7}

X - 71 = 7*1.28

X = 80

The lowest score on the final exam that would qualify a student for an​ A is 80.

Lowest score for a B:

70th percentile, which is X when Z has a pvalue of 0.7, so X when Z = 0.525.

Z = \frac{X - \mu}{\sigma}

0.525 = \frac{X - 71}{7}

X - 71 = 7*0.525

X = 74.68

The lowest score on the final exam that would qualify a student for a B is 74.68.

Lowest score for a C:

30th percentile, which is X when Z has a pvalue of 0.3, so X when Z = -0.525.

Z = \frac{X - \mu}{\sigma}

-0.525 = \frac{X - 71}{7}

X - 71 = 7*(-0.525)

X = 67.33

The lowest score on the final exam that would qualify a student for a C is 67.33.

Lowest score for a D:

10th percentile, which is X when Z has a pvalue of 0.1, so X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 71}{7}

X - 71 = 7*(-1.28)

X = 62

The lowest score on the final exam that would qualify a student for a​ D is 62.

4 0
3 years ago
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